The approximate area of the decagon with a side of 8cm comes to be 492.40 cm².
The side of the regular decagon = 8cm
<h3>What is a regular decagon?</h3>
A regular decagon is a polygon with 10 sides that are equal to each other.
The area of a regular decagon with side a is:

So, the area A of the regular decagon with a side of 8cm:


A=492.40 cm²
Therefore, the approximate area of the decagon is 492.40 cm².
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Answer:
Subtract 2 and two-thirds from both sides of the equation
8 minus 2 and two-thirds = 5 and one-third
Substitute the value for r to check the solution.
Step-by-step explanation:
2 2/3 + r = 8
Subtract 2 2/3 from each side
2 2/3 + r - 2 2/3 = 8 - 2 2/3
r = 5 1/3
Check the solution
2 2/3 +5 1/3 =8
8 =8
X1 = 3-(square root of 64) divided by 14
X2 =3+(square root of 64) divided by 14
Answer:
D) 32π in³
Step-by-step explanation:
First, we find out what r is.
We can do that because we know the area when the radius is r.
This equation can be made: <em>4π = 4/3*πr³</em>
The π's and the 4 cancel out, which gives us: <em>1 = 1/3r³</em>
This gets us 3 = r³ --> <em>r = ∛3</em> (distance can't be negative)
Now, we can plug that into the equation again: <em>V = 4/3*π(2*√3)³</em>
<em>(2∛3)³ = 24 </em>--> <em>V = 4/3*π*24</em> --> <em>V = 96/3*π </em>--> V = 32π in³
Answer:
y=5x+3
Step-by-step explanation:
You have the points (1,8) (2,13) (3,18) (4,23)
first you want to find the slope. The equation to find a slope is y2-y1 / x2-x1
your points (1,8) and (2,13) are really all you need
1 would be your x1 and your 2 would be your x2.
8 would be your y1 and 2 your y2
so you want to plug those into your equation y2-y1/x2-x1
13-8 /2-1 you get 5/1
Simplify your answer is 5 for your slope
Now finding the y intercept or "b" I normally just find the pattern of the sequence so in this case when you add one to the top your adding five to the bottom like
x 1 2 3 4
y 8 13 18 23
so to get to your y intercept which is (0,y)
subtract 1 from the top to get zero and subtract 5 from the bottom to get 3 so your y intercept is 3.
Hope this helps.