B. V=9
Multiply it out, then subtract 99 from both sides, then divide by 11
We know that one regular hexagon is consist of the six equilateral triangles.
One of this is ΔAFM every angle in this triangle worth 60°, according to this
∡AFM=60°.
ΔABC is isosceles triangle with angle ∡ABC=120°, because every interior angle in regular hexagon worth 120°.
Angles ∡BAC=∡BCA=30°. Total sum of angles in one triangle is 180°.
∡ACF≅∡BCA=30° at the end we can conclud that angle ∡FAC=90° WHY?
Good luck!!!
Answer:
The vertex form is: y = 3(x-2)^2 + 7
. The vertex is (2, 7)
Step-by-step explanation:
Write the function: y = 3x^2 - 12x + 11 in vertex form
The vertex form of a quadratic equation is:
y = m(x - a)^2 + b where (a,b) is the vertex
For y = 3x^2 - 12x + 11
Solve for m
y = 3(x^2 - 4x) + 11
Complete the Square:
y = 3(x^2 - 4x + 4) + 11 - 4
y = 3(x - 2)^2 + 7
The vertex then is (2, 7)
To prove that <span>AEC≅ AED, we need to write following proofs or statement reasons.
It is given that points C and D are equidistant to point A. Hence,
</span><span>AD ≅ AC
Next, </span><span>CAE ≅ DAE. AE is the common side or the included side.
</span><span>
Then, </span><span>AE ≅ EA by Reflexive Property of Congruence as it is congruent to itself.
Lastly, </span><span>EAD ≅ EAC by Symmetric Property of Congruence as these triangles are mirror image of each other.
</span>
Therefore, we can conclude that AEC≅ AED by SSS or Side-Side-Side. That is when all sides of triangles are congruent then both triangles are deemed to be equal.
