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Nookie1986 [14]
2 years ago
14

Find the product. (2m+5)^3

Mathematics
2 answers:
dalvyx [7]2 years ago
7 0

Answer:

8m3+60m2+150m+125

Step-by-step explanation:

(2m+5)*(2m+5)*(2m+5)

=(2m+5)(4m2+20m+25)

=(2m)(4m2)+(2m)(20m)+(2m)(25)+(5)(4m2)+(5)(20m)+(5)(25)

=8m3+40m2+50m+20m2+100m+125

=8m3+60m2+150m+125

Savatey [412]2 years ago
3 0

Answer:

8m+125 because 2^3 is 8 and m just stays the same and 5^3 is 125 so it is 8m+125

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The point (Negative StartFraction StartRoot 2 EndRoot Over 2 EndFraction, StartFraction StartRoot 2 EndRoot Over 2 EndFraction)
sveticcg [70]

The values of cosine Ф and cotangent Ф are \frac{-\sqrt{2} }{2} and -1

Step-by-step explanation:

When a terminal side of an angle intersect the unit circle at

point (x , y), then:

  • The x-coordinate is equal to cosine the angle between the positive part of x-axis and the terminal side
  • The y-coordinate is equal to sine the angle between the positive part of x-axis and the terminal side
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  • If x-coordinate is negative and y-coordinate is positive, then the angle lies in the 2nd quadrant
  • If x and y coordinates are negative, then the angle lies in the 3rd quadrant
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∵ The terminal ray of angle Ф intersects the unit circle at point (\frac{-\sqrt{2} }{2},\frac{\sqrt{2} }{2})

- According to the 1st and 2nd notes above

∴ cosФ = x-coordinate of the point

∴ sinФ = y-coordinate of the point

∵ The x-coordinate of the point is negative

∵ They-coordinate of the point is positive

- According the the 4th note above

∴ Angle Ф lies in the 2nd quadrant

∵ x-coordinate = \frac{-\sqrt{2} }{2}

∴ cosФ = \frac{-\sqrt{2} }{2}

∵ y-coordinate = \frac{\sqrt{2} }{2}

∴ sinФ = \frac{\sqrt{2} }{2}

- cotФ is the reciprocal of tanФ

∵ tanФ = sinФ ÷ cosФ

∴ cotФ = cosФ ÷ sinФ

∴ cotФ = \frac{-\sqrt{2} }{2} ÷ \frac{\sqrt{2} }{2}

∴ cotФ = -1

The values of cosine Ф and cotangent Ф are \frac{-\sqrt{2} }{2} and -1

Learn more:

You can learn more about the trigonometry function in brainly.com/question/4924817

#LearnwithBrainly

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