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Maru [420]
3 years ago
5

. If the radius is doubled and the height is halved what is the ratio of the new volume to the original volume

Mathematics
1 answer:
photoshop1234 [79]3 years ago
8 0

Answer: Ratio of new volume to original volume is 2:1.

Step-by-step explanation:

Let the radius of cylinder be 'r'

Let the height of cylinder be 'h'

Original volume of cylinder will be

V=\pi r^2h

If radius get doubled,

New radius be '2r'

If height get halved,

New height be will be

\frac{h}{2}

so, Volume of cylinder becomes

Volume=\pi (2r)^2\times \frac{h}{2}=\pi \times 4r^2\times \frac{h}{2}\\\\Volume=2\pi r^2h

Ratio of new volume to the original volume is given by

2\pi r^2h:\pi r^2h\\\\2:1

Hence, Ratio of new volume to original volume is 2:1.

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A, 69, and b will equal 180 since it forms a straight line

A+69+b=180

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Answer with Step-by-step explanation:

We are given that an equation of curve

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By using implicit differentiation, differentiate w.r.t x

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Using formula :\frac{dx^n}{dx}=nx^{n-1}

\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=-\frac{2}{3}x^{-\frac{1}{3}}

\frac{dy}{dx}=\frac{-\frac{2}{3}x^{-\frac{1}{3}}}{\frac{2}{3}y^{-\frac{1}{3}}}

\frac{dy}{dx}=-\frac{x^{-\frac{1}{3}}}{y^{-\frac{1}{3}}}

Substitute the value x=-3\sqrt3,y=1

Then, we get

\frac{dy}{dx}=-\frac{(-3\sqrt3)^{-\frac{1}{3}}}{1}

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Slope of tangent=m=\frac{1}{\sqrt3}

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y-y_1=m(x-x_1)

Substitute the values then we get

The equation of tangent line is given by

y-1=\frac{1}{\sqrt3}(x+3\sqrt3)

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