Answer:
7536 
Step-by-step explanation:
Given that:
Rate of decreasing of radius = 12 km/sec
Height of cylinder is fixed at = 2.5 km
Radius of cylinder = 40 km
To find:
The rate of change of Volume of the cylinder?
Solution:
First of all, let us have a look at the formula for volume of a cylinder.

Where
is the radius and
is the height of cylinder.
As per question statement:
= 40 km (variable)
= 2.5 (constant)

As
are constant:

2) longest line is (-1, -3) and (-1, 7)
3) (-1, -3), (-6,2), and (2,4)
Answer:
18.174x
Step-by-step explanation:
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