Answer:
(1)
Step-by-step explanation:
We will try:
(1) y = x => 2 = 2 (seems legit)
(2) y = 4x => 2 = 32 (nope)
(3) y = x - 6 => 2 = 2 (yes but actually no because it is proportional relationship)
(4) y = x - 2 => 2 = 2 (like the above)
Jamal wants to build a rectangular enclosure for his animals. One side of the pen will be against the barn, so he needs no fence
on that side. The other three sides will be enclosed with wire fencing. If Jamal has 700 feet of fencing, you can find the dimensions that maximize the area of the enclosure.
a) Let w be the width of the enclosure (perpendicular to the barn) and let l be the length of the enclosure (parallel to the barn). Write an function for the area A of the enclosure in terms of w . (HINT first write
a) Let w be the width of the enclosure (perpendicular to the barn) and let l be the length of the enclosure (parallel to the barn). Write an function for the area A of the enclosure in terms of w . (HINT first write
1 answer:
Answer:
Area of the rectangle = 700 - 2w²
Step-by-step explanation:
In the picture attached one side of the rectangle is Barn.
Two perpendicular sides of the barn are width 'w' and one parallel side to the barn is 'l'.
Jamal has the fencing having length = 700 feet
So, to cover three sides of the rectangle length of wire required = (2w + l) feet
This length should be equal to the length of the wire, which is to be used to cover these three sides.
(2w + l) = 700
l = 700 - 2w ------(1)
Area of the rectangle = lw
By replacing the value of l from equation 1
Area = w(700 - 2w)
Area = 700w - 2w²
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