Most of the money in our economy is created by banks, in the form of bank deposits – the numbers that appear in your account. Banks create new money whenever they make loans. 97% of the money in the economy today exists as bank deposits, whilst just 3% is physical cash. This short video explains:

The money that banks create isn’t the paper money that bears the logo of the government-owned Bank of England. It’s the electronic deposit money that flashes up on the screen when you check your balance at an ATM. Right now, this money (bank deposits) makes up over 97% of all the money in the economy. Only 3% of the money is still in that old-fashioned form of cash that you can touch.

I hope this helps you.

4 0

2 years ago

Which statements describe how self-reflection can benefit students? Check all that apply.

Paha777 [63]

1, 2, & 4 are ways it benefits students. The other two choices seem to be more about study skills rather than student self reflection benefits.

4 0

2 years ago

Read 2 more answers

Please help me with this question, I don't know where to exactly start

Anarel [89]

3.

A.
find the area under the curve first
$\int\limits^{\sqrt[3]{\pi}}_0 {x sin(x^3)} \, dx =0.61157809233184$
then solve c∛π=0.61157809233184
c≈0.41757577488026
round if necicary

4.
alright, solve where they itnersect

x²=y=mx
x²=mx
x²-mx=0
x(x-m)=0
set to zero

x=0

x-m=0
x=m

they intersect at x=0 and x=m

which one is on top?
hmm
y=mx will always be on top (I don't know how to prove that but it's on top)

so we do
$\int\limits^m_0 {mx-x^2} \, dx =8$
solve
$\int\limits^m_0 {mx-x^2} \, dx =[\frac{mx^2}{2}-\frac{x^3}{3}]^m_0$ $(\frac{m(m)^2}{2}-\frac{m^3}{3})-(0)=\frac{m^3}{2}-\frac{m^3}{3}=\frac{m^3}{6}=8$

so
$\frac{m^3}{6}=8$
m³=48
m=2∛6

5 0

2 years ago

Is the following argument valid or not?

evablogger [386]

Answer:

it's not valid. Jan could have still graduated from Cornell.

4 0

2 years ago