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tia_tia [17]
3 years ago
8

QS bisects mZPQR and mZPQR = 124° . Find mZPQS and mZRQS.

Mathematics
1 answer:
lakkis [162]3 years ago
8 0

Answer:

Step-by-step explanation:

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(y+3):(y+5)=k:1<br><br> show that y=(5k-3)/(1-k)<br><br> hence y=(5k-2)/(1-k)
luda_lava [24]

hi,

Express the ratios in fractional form, that is

= ( cross- multiply )

y + 3 = k(y + 5) ← distribute

y + 3 = ky + 5k ( subtract ky from both sides )

y - ky + 3 = 5k ( subtract 3 from both sides )

y - ky = 5k - 3 ← factor out y from each term on the left side

y(1 - k) = 5k - 3 ← divide both sides by (1 - k)

y = 5k- 3

____

1 - k

4 0
3 years ago
Which is greater or equal 7/10 or 9/100
Pavlova-9 [17]

9/100 is less because if we multiply 7/10 by 10 (to get an equivalent fraction with a denominator the same as the other fraction [100]) we get 70/100, which is way more than 9/100.

So, 7/10 is greater than 9/100

Hope this helps!

3 0
3 years ago
Find the value of a.<br> a<br> 52
liberstina [14]

Answer:

26

because a is gone in b than

7 0
3 years ago
Which expression below represents,”A number increased by five?”
Anna35 [415]
C
The word “increased” means to add, so C would be the correct answer. Hope this helps!
8 0
3 years ago
Read 2 more answers
Jamie is buying 5 concert tickets, and he wants his total cost to be no more than $4 Above or below $80. Which inequality models
kumpel [21]

Answer:

Option C \left|80-5x\right|\le 4

Step-by-step explanation:

Let

x ----> the cost of the concert ticket

we know that

The total cost to be no more than $4 Above  $80

so

5x\leq 80+4

Solve for x

x\leq \$16.80

The total cost to be no more than $4  below $80

so

5x\geq 80-4

Solve for x

5x\geq 76

x\geq \$15.2

therefore

The inequality that represent this problem is

\left|5x-80\right|\le 4

<u><em>Verify</em></u>

<em>First solution (positive case</em>)

+(5x-80)\le 4

5x\le 80+4

Solve for x

x\leq \$16.80 ----> is ok

<em>Second solution (negative case)</em>

-(5x-80)\le 4

Multiply by -1 both sides

(5x-80)\ge -4

5x\geq 80-4

Solve for x

5x\geq 76

x\geq \$15.2 ---> is ok

Remember that

\left|5x-80\right|\le 4 is equivalent to \left|80-5x\right|\le 4

Because is a absolute value

8 0
3 years ago
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