QS bisects mZPQR and mZPQR = 124° . Find mZPQS and mZRQS.

Mathematics

1 answer:

lakkis [162]3 years ago

8 0

Answer:

Step-by-step explanation:

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Question 20: Please help what are sin x and cos x?

sweet [91]

Answer:

A is the correct answer.

Step-by-step explanation:

$\tan x = \frac{6}{8} = \frac{opposite \: side \: to \: \angle \: x}{adjacent \: side \: to \: \angle \: x} \\ \\ hypotenuse \\ = \sqrt{ {(opp. \: side)}^{2} + {(adj. \: side)}^{2} } \\ = \sqrt{ {6}^{2} + {8}^{2} } \\ = \sqrt{36 + 64} \\ = \sqrt{100} \\ = 10 \\ \\ \because \sin (x) = \frac{opposite \: side \: to \: \angle \: x}{hypotenuse} \\ \\ \huge{ \red{ \boxed{\therefore \: \sin (x) = \frac{6}{10}}}} \\ \\ \cos (x) = \frac{adjacent \: side \: to \: \angle \: x}{hypotenuse} \\ \\ \huge{ \purple{ \boxed{\therefore \: \cos (x) = \frac{8}{10} }}} \\$