Answer:
A = mean: 30.7 median:29 mode:29
B= mean
C=median
Answer:
<h3>132°</h3>
Step-by-step explanation:
If line PS has midpoint a Q and ray QR, then line PQS will be a straight line and <PQR + <RQS = 180 (sum of angle on a straight line).
Given
<PQR = 3x-6
<RQS = x+ 2
To get x, we will use the relationship above;
3x-6+x+2 = 180
4x-4 = 180
add 4 to both sides
4x-4+4 = 180+4
4x = 184
x = 184/4
x = 46
Since <PQR = 3x-6, we will substitute the value of x into the formula;
<PQR = 3x-6
<PQR = 3(46)-6
<PQR = 138-6
<PQR = 132°
Hence the size of angle PQR is 132°
Let x = number of lines
x/3 = r2 2,5,8,11,14,17,20,23,26,29,32,35,38,41,44,47
x/5 = r2 2,7,12,17,22,27,32,37,42,47
x/7 = r5 5,12,19,26,33,40,47
47 is the smallest number that fits all 3 requirements.
The picture is not on there. If you put the picture on there maybe I can help you.
Answer:
C
Step-by-step explanation: