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Andreas93 [3]
3 years ago
5

What is the slope of (-3,4) and (5,8)

Mathematics
1 answer:
vladimir1956 [14]3 years ago
4 0

Answer:

m = 1/2

Step-by-step explanation:

Use the slope formula to find the slope <em>m</em>.

y2 - y1 / x2 - x1

8 - 4 / 5 - (-3) two negatives turn into positive.

8 - 4 / 5 + 3

4 / 8 = 1/2

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3 years ago
g A random sample of size 16 taken from a normally distributed population revealed a sample mean of 50 and a sample variance of
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Answer:

The  upper limit is    

                   k =  52.94

Step-by-step explanation:

From the question we  told that

     The  sample size is n =  16

      The sample mean is  \= x =  50

      The sample variance is  \sigma ^2  =  36

For  a  95% confidence interval the confidence level is  95%

Given that the confidence level is 95% then the level of significance is  mathematically evaluated  as  

             \alpha  =  100 - 95

              \alpha  =  5 \%

              \alpha  = 0.05

Next we obtain the critical value of  \frac{\alpha }{2} from the normal distribution table(reference- math dot armstrong dot edu), the value is  

              Z_{\frac{ \alpha }{2} } =  1.96

             

Generally the margin of error is mathematically represented as

             E =  Z_{\frac{\alpha }{2} } *  \frac{\sigma}{\sqrt{n} }

 Here  \sigma is the standard deviation which is mathematically evaluated as

                  \sigma =  \sqrt{\sigma^2}

substituting values

                  \sigma =  \sqrt{36}

=>                \sigma = 6

So

                    E = 1.96  *  \frac{6}{\sqrt{16} }

                     E = 2.94

The 95% confidence interval is mathematically represented as

                 \= x  - E  <  \mu <  \= x  + E

substituting values

                50 -2.94   <  \mu

                47.06 <  \mu

The  upper limit is    

                   k =  52.94

   

                 

7 0
3 years ago
Question 2 (2 points)
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