Since the degree of this polynomial is 5, there will be 5 possible zeros. To find the possible rational 0s, use the rational root theorem (p/q). P is the last, non x value, which here it is the four on the end. The q is the leading coefficient, which is also q. Next, find all of the factors of q and p, which since they are both 4, are ±1, ±2, and ±4. Next do all possible values of p/q, which are ±1, ±2, ±4, ±1/2, and ±1/4. These are all your possible rational zeros. complex 0s only come in pairs, so the maximum there can be is 4 complex zeros, meaning there is at least one rational, real 0. (i graphed it it is -1/2, so all others must be rational or imaginary)
Answer:
Hi! The correct answer is -5/6
Step-by-step explanation:
<em><u>~Simplify the Expression~</u></em>
Answer:
y≤3
Step-by-step explanation:
5y+4≤22−y
<em>Step 1: Simplify both sides of the inequality.</em>
5y+4≤−y+22
<em>Step 2: Add y to both sides.</em>
5y+4+y≤−y+22+y
6y+4≤22
<em>Step 3: Subtract 4 from both sides.</em>
6y+4−4≤22−4
6y≤18
<em>Step 4: Divide both sides by 6.</em>
6y/6≤18/6
y≤3
Answer:
the answer is 12
Step-by-step explanation:
