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Brilliant_brown [7]
3 years ago
5

Find the difference.

Mathematics
2 answers:
sukhopar [10]3 years ago
6 0

Answer:

-2x-4

Step-by-step explanation:

(-7x-7y-4)-(-5x-7y)=-7x-7y-4+5x+7y=-7x-4+5x=-2x-4

adoni [48]3 years ago
6 0

Answer:

-2x - 4

Step-by-step explanation:

  • (- 7x - 7y - 4) - (-5x - 7y)              Remove both sets of brackets
  • -7x - 7y - 4 + 5x + 7y                   Notice the sign change in 6x and 7y Two minus signs multiplied together make a plus. Gather like terms.
  • -7x + 5x - 7y + 7y - 4                   Simplify
  • -2x - 4                                          Note the ys cancel out.

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Container A has radius ​r​ and height h . It holds a maximum of 44 ounces of water. Container B has radius 2.5r and height 4h .
Dennis_Churaev [7]
Set an equation:

\pi  r^{2} h=44
divide both sides by 3.14
r^{2} h=14

\pi  (2.5r)^{2} 4h=x
divide both sides by 6.25, 4, and 3.14
r^{2} h=x/78.5

Since these two equations are equal, we can set them up that way.

x/78.5=14
multiply both sides by 78.5
x=1099

Answer: The maximum amount of water that container B can hold is 1,099 ounces. 

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4 years ago
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irakobra [83]
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3 years ago
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ELEN [110]
(8) =b

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6 0
3 years ago
F(x)=6x^3 - 3x^2 4x- 15 for x = -3.5
Airida [17]

Answer:

Factor by grouping. (3r + 5)(r-3)

Step-by-step explanation:

8 0
4 years ago
Adrian dog ate 40 cans of dog food in 30 days how many cans of dog food for 6 days
babunello [35]
Alright! In order to solve this problem you first have to find how how many cans of dog food he ate in one day. To do that you simply divide 40 cans by 30 days:

\frac{40}{30} → \frac{4}{3}

If the dog ate \frac{4}{3} per day, then to find out how many cans he ate in 6 days to multiply \frac{4}{3} by 6:

\frac{4}{3} x 6 → \frac{4}{3} x \frac{6}{1} = \frac{24}{3}

\frac{24}{3} simplified is 8!

Adrian's dog at 8 cans of food in 6 days.
5 0
3 years ago
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