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Brilliant_brown [7]
3 years ago
5

Find the difference.

Mathematics
2 answers:
sukhopar [10]3 years ago
6 0

Answer:

-2x-4

Step-by-step explanation:

(-7x-7y-4)-(-5x-7y)=-7x-7y-4+5x+7y=-7x-4+5x=-2x-4

adoni [48]3 years ago
6 0

Answer:

-2x - 4

Step-by-step explanation:

  • (- 7x - 7y - 4) - (-5x - 7y)              Remove both sets of brackets
  • -7x - 7y - 4 + 5x + 7y                   Notice the sign change in 6x and 7y Two minus signs multiplied together make a plus. Gather like terms.
  • -7x + 5x - 7y + 7y - 4                   Simplify
  • -2x - 4                                          Note the ys cancel out.

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3x + 2y = 8<br> -4y - 6x = -8
siniylev [52]

Answer:hg68

Step-by-step explanation:

4 0
3 years ago
(a) How many integers from 1 through 1,000 are multiples of 2 or multiples of 9?
DENIUS [597]

Answer:

(a)There are 500 integers from 1 through 1,000 are multiples of 2.

There are 111 integers from 1 through 1,000 are multiples of 9.

(b)0.611

Step-by-step explanation:

Given the set of Integers from 1 through 1000

The least multiple of 2 is 2 and the highest multiple of 2 in the interval is 1000.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 2,4,6,... is an Arithmetic Progression,

where first term, a =2, common difference, d =2

Nth term of an A.P,

U_n= a+(n-1)d\\1000=2+2(n-1)\\1000=2+2n-2\\1000=2n\\n=500

  • There are 500 integers from 1 through 1,000 are multiples of 2.

Similarly,

Given the set of Integers from 1 through 1000

The least multiple of 9 is 9 and the highest multiple of 9 in the interval is 999.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 9,18,27,... is an Arithmetic Progression,

where first term, a =9, common difference, d =9

Nth term of an A.P,

U_n= a+(n-1)d\\999=9+9(n-1)\\999=9+9n-9\\999=9n\\n=111

  • There are 111 integers from 1 through 1,000 are multiples of 9.

(b)Probability that an integer selected at random is a multiple of 2 or a multiple of 9.

There are a total of 1000 numbers between from 1 through 1,000

n(S)=1000

n(Multiples of 2)=500

n(Multiples of 9)=111

Therefore:

P(\text{Multiples of 9}) \:OR\: P(\text{Multiples of 2})=\frac{111}{1000} + \frac{500}{1000} \\=\frac{611}{1000} \\=0.611

7 0
3 years ago
What is the volume and surface area of the figure below?
Artist 52 [7]

Answer:

51.8125 yd (not rounded)

3 0
3 years ago
Find x if f(x)=2x+7 and f(x)=-1
Natalija [7]

Answer:

x = -4

Step-by-step explanation:

~~~~~~f(x) = -1\\\\\implies 2x +7 = -1\\\\\implies 2x = -1 - 7\\\\\implies 2x = -8 \\\\\implies x = -\dfrac 82 \\\\\implies x = -4

7 0
2 years ago
Give four pairs of prime numbers whose difference is 2​
zubka84 [21]

Answer:

(3, 1) (5, 3) (7, 5) (13, 11)

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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