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3 years ago

What is 7/10 minus 1/2

2 answers:

7 0

$\frac{7}{10}-\frac{1}{2}=\frac{7}{10}-\frac{1\cdot5}{2\cdot5}=\frac{7}{10}-\frac{5}{10}=\frac{2}{10}=\frac{2:2}{10:2}=\frac{1}{5}\\\\\\------------------------------\\\\\frac{7}{10}-\frac{1}{2}=0.7-0.5=0.2$

Ad libitum [116K]3 years ago

6 0

$7/10\ minus\ 1/2= \frac{7}{10} - \frac{1}{2} = \frac{7}{10} - \frac{1\cdot5}{2\cdot5}=\frac{7}{10} - \frac{5}{10} =\frac{2}{10}=\frac{1}{5}$

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What is 3 x -2? Please answer quickly!!!

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Answer: -6

Step-by-step explanation:

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3 years ago

A rope is 56 in length and must be cut into two pieces. If one piece must be six times as long as the other, find the length of

antoniya [11.8K]

Answer:

8 inches

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total 56 inches

Step-by-step explanation:

x+6x = 56

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5 0

3 years ago

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Find the missing measures of the parallelogram UT= ST= VS= VT=

12345 [234]

Answer:

see explanation

Step-by-step explanation:

In a parallelogram

• opposite sides are congruent

• the diagonals bisect each other

Then

UT = 27 ( congruent to RS )

ST = 18 ( congruent to RU )

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3 0

3 years ago

Write an equation in standard form of the line passing through the points (12, 3) and (-3, 8).

aliya0001 [1]

Answer:

x + 3y = 21

Step-by-step explanation:

$(x_{1},y_{1})=(12,3) \\\\(x_{2},y_{2})=(-3,8)\\\\Slope= \dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\= \dfrac{8-3}{-3-12}= \dfrac{5}{-15}\\\\= \dfrac{-1}{3}$

Equation of the line: y =mx+ b

$y = \dfrac{-1}{3}x+b\\\\\\Plugin \ x = 12 \ and \ y=3 \ in \ the \ above \ equation\\\\3= \dfrac{-1}{3}*12+b\\\\3= -4+b\\\\3+4 = b\\\\b = 7\\\\\\\y= \dfrac{-1}{3}x+7\\\\$

Multiply the equation by 3

3y = -x + 21

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6 0

3 years ago

7. Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

morpeh [17]

Hey there!

Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

Answer :

x = -4 or x = 2 ✅

Explanation :

Quadratic formula : ax² + bx + c = 0 where a ≠ 0

The number of real-number solutions (roots) is determined by the discriminant (b² - 4ac) :

If b² - 4ac > 0 , There are 2 real-number solutions

If b² - 4ac = 0 , There is 1 real-number solution.

If b² - 4ac < 0 , There is no real-number solution.

The roots of the equation are determined by the following calculation:

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}$

Here, we have :

a = 1
b = 2
c = -8

1) Calculate the discriminant :

b² - 4ac ⇔ 2² - 4(1)(-8) ⇔ 4 - (-32) ⇔ 36

b² - 4ac = 36 > 0 ; The equation admits two real-number solutions

2) Calculate the roots of the equation:

▪️ (1)

$x_1 = \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x_1 = \frac{ - 2 - \sqrt{36} }{2(1) } \\ \\ x_1 = \frac{ - 2 - 6}{2} \\ \\ x_1 = \frac{ - 8}{2} \\ \\ \blue{\boxed{\red{x_1 = -4}}}$

▪️ (2)

$x_2 = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ x_2 = \frac{ - 2 + \sqrt{36} }{2(1)} \\ \\ x_2 = \frac{ - 2 + 6}{2} \\ \\ x_2 = \frac{4}{2} \\ \\ \red{\boxed{\blue{x_2 = 2}}}$

>> Therefore, your answers are x = -4 or x = 2.

Learn more about quadratic equations:

brainly.com/question/27638369

6 0

2 years ago

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