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gayaneshka [121]
3 years ago
14

What is the right answer to this question (2x-5) (x+2)

Mathematics
1 answer:
Tpy6a [65]3 years ago
3 0

Answer:

2x² - x - 10

Step-by-step explanation:

Given

(2x - 5)(x + 2)

Each term in the second factor is multiplied by each term in the first factor, that is

2x(x + 2) - 5(x + 2) ← distribute both parenthesis

= 2x² + 4x - 5x - 10 ← collect like terms

= 2x² - x - 10

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Answer:

jupiter, Saturn, Uranus, neptune are all distance from sun

Step-by-step explanation:

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2 years ago
Find the distance from the point (4,2) to the point (0,1).
vagabundo [1.1K]

Answer:

4.123 units

Step-by-step explanation:

Data provided:

Coordinates of point 1 as ( 4 , 2)

and,

Coordinates of point 2 as ( 0 , 1 )

Now,

The distance between the two point whose coordinates are given is calculated using the formula as:

distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

on substituting the values, we get

distance = \sqrt{(0-4)^2+(1-2)^2}

or

distance = \sqrt{(-4)^2+(-1)^2}

or

distance = \sqrt{16+1}

or

Distance = √17 = 4.123 units

6 0
3 years ago
Simplify the expression. tan(sin^−1 x)
Blizzard [7]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2799412

_______________


Let  \mathsf{\theta=sin^{-1}(x)\qquad\qquad-\dfrac{\pi}{2}\ \textless \ \theta\ \textless \ \dfrac{\pi}{2}.}

(that is the range of the inverse sine function).


So,

\mathsf{sin\,\theta=sin\!\left[sin^{-1}(x)\right]}\\\\ \mathsf{sin\,\theta=x\qquad\quad(i)}


Square both sides:

\mathsf{sin^2\,\theta=x^2\qquad\qquad(but~sin^2\,\theta=1-cos^2\,\theta)}\\\\ \mathsf{1-cos^2\,\theta=x^2}\\\\ \mathsf{1-x^2=cos^2\,\theta}\\\\ \mathsf{cos^2\,\theta=1-x^2}


Since \mathsf{-\,\dfrac{\pi}{2}\ \textless \ \theta\ \textless \ \dfrac{\pi}{2},} then \mathsf{cos\,\theta} is positive. So take the positive square root and you get

\mathsf{cos\,\theta=\sqrt{1-x^2}\qquad\quad(ii)}


Then,

\mathsf{tan\,\theta=\dfrac{sin\,\theta}{cos\,\theta}}\\\\\\ \mathsf{tan\,\theta=\dfrac{x}{\sqrt{1-x^2}}}\\\\\\\\ \therefore~~\mathsf{tan\!\left[sin^{-1}(x)\right]=\dfrac{x}{\sqrt{1-x^2}}\qquad\qquad -1\ \textless \ x\ \textless \ 1.}


I hope this helps. =)


Tags:  <em>inverse trigonometric function sin tan arcsin trigonometry</em>

3 0
3 years ago
Read 2 more answers
Write the following decimals as fractions.
GaryK [48]

Hi there! Hopefully this helps!

-------------------------------------------------------------------------------------------------------

<em>0.77</em><em> </em><em>as a </em><u><em>fraction</em></u><em> is </em><u><em>77/100</em></u><em>.</em>

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

<em>0.2904 as a </em><u><em>fraction</em></u><em> is </em><u><em>2904⁄10000</em></u><em> </em><u><em>unsimplified</em></u><em>. (Simplified would be </em><u><em>363⁄1250</em></u><em>)</em>

6 0
4 years ago
Read 2 more answers
If 1+1 =2<br> then what does 2+1=?
konstantin123 [22]

Answer:

3

Step-by-step explanation:

if 1+1=2

than 2+1=3..

hope it is helpful

8 0
3 years ago
Read 2 more answers
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