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seraphim [82]
3 years ago
14

Two passenger train, A and B, 450 km apart, star to move toward each other at the same time and meet after 2hours.

Mathematics
1 answer:
likoan [24]3 years ago
5 0

Let v be the speed of train A, and let's set the origin in the initial position of train A. The equations of motion are

\begin{cases}s_A(t) = vt\\s_B(t) = -\dfrac{8}{7}vt+450\end{cases}

where s_A,\ s_B are the positions of trains A and B respectively, and t is the time in hours.

The two trains meet if and only if s_A=s_B, and we know that this happens after two hours, i.e. at t=2

\begin{cases}s_A(2) = 2v\\s_B(2) = -\dfrac{16}{7}v+450\end{cases}\implies 2v = -\dfrac{16}{7}v+450

Solving this equation for v we have

2v = -\dfrac{16}{7}v+450 \iff \dfrac{30}{7}v=450 \iff v=\dfrac{450\cdot 7}{30} = 105

So, train A is travelling at 105 km/h. This implies that train B travels at

105\cdot \dfrac{8}{7} = 15\cdot 8=120 \text{ km/h}

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