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Cloud [144]
3 years ago
14

The oxygen consumption (in milliliter per pound per minute) for a person walking at x mph is approximated by the function f(x)=\

frac{5}{3} x^{2}+\frac{5}{3} x+10 \quad(0 \leq x \leq 9)whereas the oxygen consumption for a runner at x mph is approximated by the function g(x)=11 x+10 \quad(4 \leq x \leq 9) b. At what speed is the oxygen consumption the same for a walker as it is for a runner? What is the level of oxygen consumption at that speed?
Mathematics
1 answer:
Oliga [24]3 years ago
3 0

Answer: Speed = 5.6 mph

              Oxygen consumption = 71.6 mL/lb/min

Step-by-step explanation: For the oxygen consumption to be the same, functions must be equal:

f(x) = g(x)

\frac{5}{3}.x^{2} + \frac{5}{3}.x+10=11x+10

Resolving:

\frac{5}{3}.x^{2} + \frac{5}{3}.x - 11x =0

\frac{5}{3}x^{2} + \frac{5}{3}x - \frac{33x}{3}=0

\frac{5}{3}x^{2}  - \frac{28x}{3}=0

\frac{x}{3}(5x  - 28)=0

\frac{x}{3} = 0

x=0

5x - 28 = 0

x = \frac{28}{5}

x = 5.6

<u>The speed when the oxygen consuption is the same is </u><u>5.6 mph</u><u>.</u>

For the level of oxygen consumption:

f(5.6) = g(5.6)

g(5.6) = 11*5.6 + 10

g(5.6) = 71.6

<u>The level of oxygen consumption is </u><u>71.6 mL/lb/min</u>

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In constructing a 95 percent confidence interval, if you increase n to 4n, the width of your confidence interval will (assuming
Damm [24]

Answer:

about 50 percent of its former width.

Step-by-step explanation:

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\hat \theta \pm ME(\hat \theta)

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Now if we find the width for a confidence interval we got this:

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If we increase the sample size from n to 4n now our width is:

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about 50 percent of its former width.

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