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3 years ago

10

D= m/v [stack friction] , where d = density, m = mass, and v = volume. If a rock has a density of 10 g/cm3 and a volume of 15 cm

3 , what is its mass?

1 answer:

Cloud [144]3 years ago

8 0

150 g/cm3
Write your equation out with known variables.

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Tom [10]

The answers are A and E!

6 0

3 years ago

These types of electromagnetic waves are listed in order of increasing frequency:

xenn [34]

Answer:

B. X-rays

Explanation:

From the given choices, x-rays will have the highest energy of the given waves.

The energy of electromagnetic waves is highly dependent on their frequency and wavelength.

Electromagnetic waves with a high frequency and small wavelength will have higher energy compared to those with low frequency and high wavelength.

X-rays are one the most energetic waves on the periodic table. They have a very high frequency and low wavelength.

7 0

3 years ago

Read 2 more answers

The 60.0 kg skier shown below is skiing down a 35.0 degree incline where the magnitude of the friction force is 38.5N

Sunny_sXe [5.5K]

Answer:

a) 4.98m/s²

b) 481.66N

Explanation:

a) Using the Newtons second law of motion

$\sum F_x = ma_x\\F_m - F_f = ma_x\\Wsin \theta - F_f = ma_x\\mgsin \theta - F_f = ma_x\\$

m is the mass of the object

g is the acceleration due to gravity

Fm is the moving force acting along the plane

Ff is the frictional force opposing the moving froce

a is the acceleration of the skier

Given

m = 60kg

g = 9.8m/s²

$\theta$ = 35°

Ff = 38.5N

Required

acceleration of the skier a

Substituting into the formula;

$60(9.8)sin 35^0 - 38.5 = 60a\\588sin35^0 - 38.5 = 60a\\337.26 - 38.5 = 60a\\298.76 = 60a\\a = 298.76/60\\a = 4.98m/s^2\\$

Hence the acceleration of the skier is 4.98m/s²

b) The normal force on the skier is expressed as;

N = Wcosθ

N = mgcosθ

N = 60(9.8)cos 35°

N = 588cos 35°

N = 481.66N

Hence the normal force on the skier is 481.66N

5 0

3 years ago

Why are men typically less stable on their feet than women

Viktor [21]

Women generally have a lower centre of gravity than men, contributing to greater stability. Men generally have more muscle mass in their upper bodies,

8 0

4 years ago

Read 2 more answers

An old-fashioned LP record rotates at 33 1/3 RPM

Ksenya-84 [330]

Answer:

Part a) $\frac{5}{9}\ \frac{rev}{sec}$

Part b) $\frac{9}{5}\ \frac{sec}{rev}$

Explanation:

Part a) what is its frequency, in rev/s

we have that

An old-fashioned LP record rotates at 33 1/3 RPM

so

$33\frac{1}{3}\ \frac{rev}{min}$

Convert mixed number to an improper fraction

$33\frac{1}{3}\ \frac{rev}{min}=\frac{33*3+1}{3}=\frac{100}{3}\ \frac{rev}{min}$

Remember that

$1\ min=60\ sec$

Convert rev/min to rev/sec

$\frac{100}{3}\ \frac{rev}{min}=\frac{100}{3}(\frac{1}{60})=\frac{100}{180}\ \frac{rev}{sec}$

Simplify

$\frac{5}{9}\ \frac{rev}{sec}$

Part b) what is it period, in seconds

we know that

The period is the reciprocal of the frequency

therefore

the frequency is

$\frac{9}{5}\ \frac{sec}{rev}$

4 0

3 years ago