Answer:
Real values of x where x < -1
Step-by-step explanation:
Above the x-axis, the function is positive.
The function is decreasing when the gradient is negative.
The function has a positive

coefficient, therefore the vertex is a local minimum;
This means the gradients are negative before the vertex and positive after it;
To meet the conditions therefore, the function must be before the vertex and above the x-axis;
This will be anywhere before the x-intercept at x = -1;
Hence it is when x < -1.
The
slope is the change in y divided by the change in x.
The
slope is the ratio of rise to run.
The
slope is the rate of change of the function at a certain point.
The
slope is the first derivative of a function.
Accordingly, the slope of this line <span>d=420-65t is the coefficient of variable "t" if we consider that d for the dependent variable and t for the independent
Therefore
slope =
- 65</span>
I hope you got
the idea
14 is the answer for this one