All categories

3 years ago

Construct a graph corresponding to the linear equation .

1 answer:

5 0

Since you have a linear equation, in order to draw its graph you just need two points in the cartesian plain. To find this points solve the equation firstly when y=0 and secondly when x=0. After that you have your two points and all you have to do is connect the corresponding dots.

You might be interested in

H(x)=x−4h<br> What is the domain of h?

MAVERICK [17]

Answer:

h= x/ x+4

Step-by-step explanation:

Move all terms to the left side and set equal to zero, Then set each factor equal to zero.

3 0

3 years ago

The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0

3 years ago

In a poll of Mr. Briggs's math class, 67% of the students say that math is their favorite academic subject. The editor of the sc

levacccp [35]

Mathematics is the subject that is most popular in the class and is liked by the students.

<u>Explanation:</u>

Among all the subjects that are added in the curriculum of the students in the school, Mathematics is the subject that is mostly liked by the students in the class and in the school.

To find this that mathematics was the favorite subject of the students, a a survey was conducted by the school people in the class of a professor and through that survey it was shown that Mathematics was a subject that was mostly liked by all the students.

4 0

3 years ago

The sum of three consecutive integers is −42. find the three integers.

erica [24]

Let the integers be x - 1, x and x + 1, then
x - 1 + x + x + 1 = -42
3x = -42
x = -42/3 = -14

The three consectutive integers are -15, -14 and -13

4 0

4 years ago

A triangle has sides of length 3 cm and 3 cm. What can be concluded about the length of the third side?

mrs_skeptik [129]

Answer:

that its 3cm

Step-by-step explanation:

7 0

2 years ago