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forsale [732]
3 years ago
12

Mark, David, Tia, and Ashley are team members in a computer programming class. They have been assigned the task of creating a co

mputerized payroll system. Mark and Tia worked very hard and created programs that worked well. David and Ashley, however, did not work as hard as they could and created programs with numerous errors. This resulted in a payroll system which could not be implemented. The team's poor performance that was a result of David and Ashley not doing their best can be termed as______________.
A. groupthink.
B. synergy.
C. social facilitation.
D. hierarchical sensitivity.
E. motivational loss.
Computers and Technology
1 answer:
11Alexandr11 [23.1K]3 years ago
6 0

The team's poor performance that was a result of David and Ashley not doing their best can be termed as groupthink.

A. groupthink.

<u>Explanation:</u>

To generate payroll system task been as four member (David, Mark Tia, and Ashley) team, when TIA and Mark worked and completed the payroll task. At same time David and Ashley did not work hard to complete task payroll generation system.

Both David and Ashley not understand the program or group thinking is not done.

So it is groupthink is not done by David and Ashley properly. At same time MARK AND TIA able complete means groupthink done properly.

Result of payroll system is total failure.

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Creating a Graphical User Interface in Java
tankabanditka [31]

Answer:

JPanel PayrollPanel=new JPanel();

JButton saveButton=new JButton("Save");

A full code snippet and screen shot is provided in the explanation section

Explanation:

import java.awt.*;

import javax.swing.*;

public class TestClass {

   TestClass()  {

       JFrame f= new JFrame("Payroll Panel");

       JPanel payrollPanel=new JPanel();

       payrollPanel.setBounds(10,20,200,200);

       payrollPanel.setBackground(Color.gray);

       JButton saveButton=new JButton("Save");

       saveButton.setBounds(50,100,80,30);

       saveButton.setBackground(Color.yellow);

       payrollPanel.add(saveButton);

       f.add(payrollPanel);

       f.setSize(400,400);

       f.setLayout(null);

       f.setVisible(true);

   }

   public static void main(String args[]) {

       new TestClass();

   }

}

4 0
4 years ago
Codio Challenge Question (Python)
Agata [3.3K]

Answer:

if speed1 > 70 or speed2 > 70:

print("fast cars")

else:

print("ok")

Explanation:

This is some very simple logic that will satisfy the requirements, we need to compare each speed against our speed limit (70) and if either (or) have exceeded it (>) then we need to output (print) "fast cars", otherwise we output "ok".

7 0
3 years ago
This program will store roster and rating information for a soccer team. Coaches rate players during tryouts to ensure a balance
aksik [14]

Answer:

import java.util.Scanner;

public class TeamRoster {

  public static void main(String[] args) {

     Scanner scan = new Scanner(System.in);

     int[][] players = new int[5][2];

     boolean keepAlive = true;

     char input;

     

     for (int i = 0; i < 5; i++) {

        System.out.println("Enter player " + (i+1) + "'s jersey number: ");

        players[i][0] = scan.nextInt();

        if( players[i][0] >= 0 && players[i][0] < 100 ) {

             System.out.println("Enter player number less than 100");

               System.out.println("Enter player " + (i+1) + "'s rating: ");

               players[i][1] = scan.nextInt();

               if ( players[i][1] >= 1 && players[i][1] <10 ) {

                     System.out.println();

               }    else {

                     System.out.println("Enter player " + (i+1) + "'s rating: ");

                     players[i][1] = scan.nextInt();

               }

     }

     }

     System.out.println();

     outputRoster(players, 0);

     

     while (keepAlive) {

        outputMenu();

        input = scan.next().charAt(0);

        if (input == 'q') {

           keepAlive = false;

           break;

        } else if (input == 'o') {

           outputRoster(players, 0);

        } else if (input == 'u') {

           System.out.println("Enter a jersey number: ");

           int jerseyNum = scan.nextInt();

           System.out.println("Enter a new rating for the player: ");

           int newRating = scan.nextInt();

           for (int l = 0; l < 5; l++) {

              if (players[l][0] == jerseyNum) {

                 players[l][1] = newRating;

              }

           }

        } else if (input == 'a') {

           System.out.println("Enter a rating: ");

           int rating = scan.nextInt();

           outputRoster(players, rating);

        } else if (input == 'r') {

           System.out.println("Enter a jersey number: ");

           int jerseyNum = scan.nextInt();

           boolean exists = true;

           for (int l = 0; l < 5; l++) {

              if (players[l][0] == jerseyNum) {

                 System.out.println("Enter a new jersey number: ");

                 players[l][0] = scan.nextInt();

                 System.out.println("Enter a rating for the new player: ");

                 players[l][1] = scan.nextInt();

              }

           }

           

        }

     }

     

     return;

  }

   

  public static void outputRoster(int[][] players, int min) {

     System.out.println(((min>0) ? ("ABOVE " + min) : ("ROSTER")));

     int item = 1;

     for (int[] player : players) {

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           System.out.println("Player " + item + " -- Jersey number: " + player[0] + ", Rating: " + player[1]);

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        item++;

     }

     System.out.println();

  }

   

  public static void outputMenu() {

     System.out.println("MENU");

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     System.out.println("r - Replace player");

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     System.out.println("q - Quit\n");

     System.out.println("Choose an option: ");  

  }

}

Explanation:

The program is written in Java.

It is a bit straightforward.

The Scanner module is declared and used to collect input from the user.

The program prompts the user for each player jersey then rating.

All five players details are collected.

The program shows the output of all the entries.

5 0
3 years ago
Given that<br>f(x) = 5x +3.<br>Find f (4)​
Vitek1552 [10]

Answer:

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3 0
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