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kolbaska11 [484]
3 years ago
13

the total is 30 coins and 3 dollars. there are twice as many nickles as dimes. how many nickles and dimes and there

Mathematics
2 answers:
beks73 [17]3 years ago
8 0

Answer:

20 nickels and 10 dimes.

BlackZzzverrR [31]3 years ago
4 0

Answer:

6=d

Step-by-step explanation:

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Obi's age is twice oba's age 4 years ago obi was three times as old as oba. find their ages​
frutty [35]

Answer:

Obi's age is 18 and Oba's age is 9

Step-by-step explanation:

Let Obi's age be x and Oba's age be y

<u><em>Condition 1:</em></u>

x = 2y -----------(1)

<u><em>Condition 2:</em></u>

(x-4) = 3(y-4)

=> x -4 = 3y-12

=> x - 3y = -9  -----(2)

<u><em>Putting eq (1) in (2)</em></u>

2y - 3y = -9

=> -y = -9

=> y = 9

Now,

x = 2y

=> x = 2(9)

=>  x= 18

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3 years ago
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A group of randomly selected members of Mothers' Club were asked how many kids they have. The table below shows the results of t
Aleksandr [31]

Answer:

C : 54

Step-by-step explanation:

8 0
3 years ago
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33 POINTS + BRAINLIEST
zubka84 [21]

Answer:

For question 2 (Triangle):

The triangle hThe entire triangle area = 2 * 13.125 =

26.25

 

Triangle perimeter both legs = 16.6 + base (7) = 23.6

For question 1 (Parallelogram):

longer congruent sides = 6-0 OR 4-(-2) = 6units

area= 3×6 = 18units^2

7 0
3 years ago
Solve (x + 5)^(3/2)= (x - 1)^3
IRINA_888 [86]

Answer:

  x = 4

Step-by-step explanation:

For an equation of this sort, my first step is to rewrite it so the solutions are the x-intercepts of the graph:

  (x +5)^(3/2) -(x +1)^3 = 0

The graph is attached. The one real solution is x=4.

__

The solution method for something like this is necessarily ad hoc. Here, it appears that progress can be made by raising both sides of the equation to the 2/3 power:

  ((x +5)^(3/2))^(2/3) = ((x -1)^3)^(2/3)

  x +5 = (x -1)^2

Now, you have an ordinary quadratic that can be solved using any of the usual methods.

  x^2 -2x +1 = x +5 . . . . swap sides, expand the square

  x^2 -3x -4 = 0 . . . . . . put in standard form

  (x -4)(x +1) = 0 . . . . . . factor

The solutions to this are ...

  x = 4, x = -1 . . . . . . . values of x that make the factors zero

__

To see if either of these solutions is extraneous, we can check them:

  (4 +5)^(3/2) = (4 -1)^3 . . . . . substitute 4 for x

  9^(3/2) = 3^3 . . . . . . . . . true

  (-1 +5)^(3/2) = (-1 -1)^3 . . . . . substitute -1 for x

  4^(3/2) = (-2)^3

  8 = -8 . . . . . . . . . . . false; x = -1 is extraneous

The solution is x = 4.

_____

<em>Additional comment</em>

You can eliminate the x=-1 "solution" by considering the domains of the left- and right-side expressions. The 3/2 power is equivalent to the square root of the cube. That will generally only be defined for non-negative values (x ≥ -5). The cube on the right will only be positive for x > 1, so the practical domain of this equation is x ≥ 1.

5 0
3 years ago
Find x<br> You use the law of sines and that’s all I know dawg
mars1129 [50]

Answer:

Was dis a question or an answer, dawg??

7 0
3 years ago
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