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Nadusha1986 [10]
3 years ago
5

16

Mathematics
2 answers:
BlackZzzverrR [31]3 years ago
6 0

Answer:

c.33.08

Step-by-step explanation:

add all of them together and you get 140.7 divded by 5 and get 33.08

7nadin3 [17]3 years ago
5 0
C because I just know
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What is Australia constitution​
Daniel [21]

Answer :

The Australian Constitution is the set of rules by which Australia is run. It came into effect on 1 January 1901. This fact sheet summarises the key features of the Constitution and how it can be changed. Commonwealth of Australia Constitution Act, 1900: Original Public Record Copy (1900).

7 0
2 years ago
What is the value of y in the formula shown when x = 4/5?
Pavlova-9 [17]
4(4/5) + √(4/5) + 0.2 - 5(4/5)

= 16/5 + (2√5/5) + (1/5) - 4

= (16 + 2√5 + 1 - 20)/5

= (2√5 - 3)/5 or 0.29442719
6 0
3 years ago
What is the maximum of f(x)= sin(x)?<br><br> -2π<br> -1<br> 1<br> 2π
nadezda [96]

Answer:

1

Step-by-step explanation:

the maximum of f(X)=sin(X) is 1

6 0
3 years ago
What % of 800,000 = 560,000​
Ne4ueva [31]

Answer:

70%

Step-by-step explanation:

560,000/800,000= 0.70

6 0
3 years ago
g "They hired an analyst who collected a random sample of 40,361 Game of Thrones fans, and found that 8,337 of those fans said t
Viktor [21]

Answer:

The lower bound for a 90% confidence interval is 0.2033.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 40361, \pi = \frac{8337}{40361} = 0.2066

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2066 - 1.645\sqrt{\frac{0.2066*0.7934}{40361}} = 0.2033

The lower bound for a 90% confidence interval is 0.2033.

6 0
3 years ago
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