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dsp73
3 years ago
7

A local lake has a fish population that follows a geometric series with these properties first time equals 48 ratio equals 1/4 d

etermine what does sun would be for the upper limit of this population after you create the sigma notation set up for it
Mathematics
1 answer:
kondaur [170]3 years ago
4 0

Answer:

64.

Step-by-step explanation:

Sigma notation is ∑48(1/4)^(n-1).

Upper limit =   a1 / (1 - r)  where a1 = initial population and r = common ratio.

So it is 48 / (1 - 1/4)

= 48 / 3/4

= 48 * 4/3

= 64.

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Option a: 4x^{3} -\frac{2}{x}

Option b: 2y^{3} +5y^{2} -5y

Option c: 3y^{3} -\sqrt{4y}

Explanation:

The highest degree of a polynomial is the largest exponent of that variable.

Now, we shall determine the polynomial with degree 3.

Option a: 4x^{3} -\frac{2}{x}

From the expression 4x^{3} -\frac{2}{x}, the highest degree of the polynomial is 3.

Hence, 4x^{3} -\frac{2}{x} is a polynomial with a degree of 3.

Hence, Option a is the correct answer.

Option b: 2y^{3} +5y^{2} -5y

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Hence, 2y^{3} +5y^{2} -5y is a polynomial with a degree of 3.

Hence, Option b is the correct answer.

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Hence, 3y^{3} -\sqrt{4y} is a polynomial with a degree of 3.

Hence, Option c is the correct answer.

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