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Elis [28]
3 years ago
10

Please help me create a function Correct answer gets brainiest :)

Mathematics
1 answer:
slega [8]3 years ago
4 0
Let y be Justin base pay, w% be commission,
y + w%*600=350-----(1)
y+w%*900= 425-----(2)
From equation (1),
y = 350- w%*600 = 350-6w-------(3)
Substitute equation (3) into (2),
350-6w+9w=425
3w = 425-350= 75
w= 25
y = 350-6w= 350-6(25)= 200
so the function is base pay +25%of merchandise
Final answer is $ (200 + 0.25x)
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D.Moving left to right, the whole number stays the same, the tenths stay the same, and the hundredths decrease by 2.

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Hello I need help with this, Don Manuel has 600m of fence to build a rectangular-shaped corral. You will take advantage of a ver
Anton [14]

Answer:  If the wall is 300 meters long, the dimensions of the fence with the maximum area will be 300 × 150 = 45000 m²

Step-by-step explanation:

try combinations in a chart

190 × (600-190)/2 = 38950  = 190 × 205       increasing area

200 × (600-200)/2 = 40000   = 200 × 200

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310 × (600-310)/2 = 44950 . == 310 × 145    decreasing area

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5 0
3 years ago
The length of the hypotenuse is:<br> 0.<br> 1.<br> 2.<br> 4.
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3 years ago
a certain pharmaceutical company know that, on average 4% of a certain type of pill has an ingredient that is below the minimum
FinnZ [79.3K]

Using the binomial distribution, it is found that there is a 0% probability that fewer that 5 in a sample of 20 pills will be acceptable.

For each pill, there are only two possible outcomes, either it is acceptable, or it is not. The probability of a pill being acceptable is independent of any other pill, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • The sample has 20 pills, hence n = 20.
  • 100 - 4 = 96% are acceptable, hence p = 0.96

The probability that <u>fewer that 5 in a sample of 20 pills</u> will be acceptable is:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{20,0}.(0.96)^{0}.(0.04)^{20} = 0

P(X = 1) = C_{20,1}.(0.96)^{1}.(0.04)^{19} = 0

P(X = 2) = C_{20,2}.(0.96)^{2}.(0.04)^{18} = 0

P(X = 3) = C_{20,3}.(0.96)^{3}.(0.04)^{17} = 0

P(X = 4) = C_{20,4}.(0.96)^{4}.(0.04)^{16} = 0

0% probability that fewer that 5 in a sample of 20 pills will be acceptable.

A similar problem is given at brainly.com/question/24863377

8 0
2 years ago
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