Dy/dx ln(xy)=e^(x+y)

Could someone help please

pogonyaev

Answer:

3.5 m/s

Step-by-step explanation

Remove brackets

d = t^2 + 0.2t + 3.3t + .66

Combine

d = t^2 + 3.5t + .66

The initial velocity is 3.5

3 0

3 years ago

For the end-of-year party, Mt.Rise Middle School ordered 112 pizzas. There were eight fewer veggie pizzas than there were pepper

rodikova [14]

Let the number of pepperoni pizzas be x
pepperoni = x
veggie = x - 8 [<span>There were eight fewer veggie than pepperoni]
</span>combo = 3x [T<span>here were three times as many combo as pepperoni]
</span>
Given that the total Pizza: 112
x + x - 8 + 3x = 112
5x - 8 = 112
5x = 112 + 8
5x = 120
x = 24

x= 24
x - 8 = 16
3x = 72

So there were 24 pepperoni pizza, 16 veggie pizza and 72 combo pizza

5 0

3 years ago

The relationship between the slopes of two lines that are parallel is _____________.

a_sh-v [17]

They are the same slope

they are negative inversees (they multily to get -1)

2

-1/2

use the square viewer (on TI)

The relationship between the slopes of two lines that are parallel is they are the same. The relationship between the slopes of two lines that are perpendicular is they are negative inverses of each other (they multiply to -1).
A line that is parallel to a line whose slope is 2 has slope 2.
A line that is perpendicular to a line whose slope is 2 has slope -1/2.

What must be done to make the graphs of two perpendicular lines appear to intersect at right angles when they are graphed using a graphing utility?

8 0

3 years ago

Read 2 more answers

A population of bees is decreasing. The population in a particular region this year is 1,250. After 1 year, it is estimated tha

8_murik_8 [283]

To model this situation, we are going to use the decay formula: $A=Pe^{rt}$
where
$A$ is the final pupolation
$P$ is the initial population
$e$ is the Euler's constant
$r$ is the decay rate
$t$ is the time in years

A. We know for our problem that the initial population is 1,250, so $P=1250$ ; we also know that after a year the population is 1000, so $A=1000$ and $t=1$ . Lets replace those values in our formula to find $r$ :
$A=Pe^{rt}$
$1000=1250e^{r}$
$e^{r}= \frac{1000}{1250}$
$e^{r}= \frac{4}{5}$
$ln(e^{r})=ln( \frac{4}{5} )$
$r=ln( \frac{4}{5} )$
$r=-02231$

Now that we have $r$ , we can write a function to model this scenario:
$A(t)=1250e^{-0.2231t}$ .

B. Here we are going to use a graphing utility to graph the function we derived in the previous point. Please check the attached image.

C.
- The function is decreasing
- The function doe snot have a x-intercept
- The function has a y-intercept at (0,1250)
- Since the function is decaying, it will have a maximum at t=0:
$A(0)=1250e^{(-0.2231)(0)$
$A_{0}=1250e^{0}$
$A_{0}=1250$
- Over the interval [0,10], the function will have a minimum at t=10:
$A(10)=1250e^{(-0.2231)(10)$
$A_{10}=134.28$

D. To find the rate of change of the function over the interval [0,10], we are going to use the formula: $m= \frac{A(0)-A(10)}{10-0}$
where
$m$ is the rate of change
$A(10)$ is the function evaluated at 10
$A(0)$ is the function evaluated at 0
We know from previous calculations that $A(10)=134.28$ and $A(0)=1250$ , so lets replace those values in our formula to find $m$ :
$m= \frac{134.28-1250}{10-0}$
$m= \frac{-1115.72}{10}$
$m=-111.572$
We can conclude that the rate of change of the function over the interval [0,10] is -111.572.

7 0

3 years ago

PLEASE HELP

katrin2010 [14]

The game that is used for the scenario above in terms of fair play is using a balloon. Here, the player will hit the balloon.

<h3>What is the scenario under the balloon game?</h3>

The rule of play are:

This is a classic game with simple rules which are:

Each player to hit the balloon up and it bonce into the air but when one should not allow it to touch the ground.,
Players would be tied together in twos and they will juggle a lot of balloon and it have to be more than 1 balloon with one of their hands tied to their back.

A scenario of the worksheet game whose expected value is 0 is given below:

Assume that it costs about $1 for a player to play the billon game and as such, if the player hits a balloon, they will be given $3. what can you say. Can you say that it this game is fair or not? and who has the biggest advantage.

Solution

Note that a game is ”fair” if the expected value is said to be 0. When a player is said to hits a balloon, their net profit often increase by $4. So when the player do not hit a balloon, it drops to $1.

(4)(0.313) + (-1)(0.313)

= 0.939 approximately

Thus, the expected value is $0.939 which tells that the game is fair.

Learn more about fair play from

brainly.com/question/24855677

#SPJ1

4 0

2 years ago