2 years ago

Dy/dx ln(xy)=e^(x+y)

1 answer:

4 0

In(xy) = e^(x+y)

(xy)'/xy = (x+y)' e^(x+y)

(x'y + xy')/xy = (1+y') e^(x+y)

(y + xy')/xy = (1+y')e^(x+y) and simplify

Hope this helps

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