The sample % of these two populations would be 100/size (of student body at each school) x 100 so this would compare the two student bodies preferences for the particular type of candy bar. However, the actual % of the whole student body at each school would be a factor also. If the high school only had 200 students then this would be 50% representative but if the middle school had say 500 students this would only be 20% representative so this would have to be taken into account too. It might be more representative to have the same % of the student bodies respectively for the sample.
4/8 + 3/8 = 7/8
or 1/2+3/8=7/8
0.5+0.375=0.875
Answer:
the answer should be D
Step-by-step explanation:
:)
I think the answer is he should've added t instead of subtracting t.
Answer:
![\frac{1}{2} \: > \: \frac{7}{15}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%20%5C%3A%20%20%3E%20%20%5C%3A%20%20%5Cfrac%7B7%7D%7B15%7D%20)
Step-by-step explanation:
We want to determine which of the following fractions is bigger.
The fractions are:
![\frac{1}{2} \: and \: \frac{7}{15}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20%20%5C%3A%20and%20%5C%3A%20%20%5Cfrac%7B7%7D%7B15%7D%20)
We collect LCM to get;
![\frac{15}{30} \: and \: \frac{14}{30}](https://tex.z-dn.net/?f=%20%5Cfrac%7B15%7D%7B30%7D%20%20%5C%3A%20and%20%5C%3A%20%20%5Cfrac%7B14%7D%7B30%7D%20)
Now that the denominators are the same we can easily compare.
![\frac{15}{30} \: > \: \frac{14}{30}](https://tex.z-dn.net/?f=%20%5Cfrac%7B15%7D%7B30%7D%20%20%5C%3A%20%20%3E%20%5C%3A%20%20%5Cfrac%7B14%7D%7B30%7D%20)
This means that:
![\frac{1}{2} \: > \: \frac{7}{15}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20%20%5C%3A%20%20%3E%20%20%5C%3A%20%20%5Cfrac%7B7%7D%7B15%7D%20)