The formula for illuminance is given by
E = I / d^2
This formula only holds true for one-dimensional illuminance
The problem asks for the illuminance across the floor. We need to use two variables, x and y.
From Pythagorean Theorem
d^2 = x^2 + y^2
and from Trigonometry
x = d cos t
y = d sin t
The function for the illuminance can be represented by the composite function
E = I cos² t / x²
and
E = I sin² t / y²
The boundary of these functions is:
<span>0 < t < 8
So, the value of t must be in radians and not in degrees</span>
The answers for the exercise shown above are the second option, the third option, the fifth option and the sixth option, which are:
2) <span>Distribute 2 to 9.7 and −4.8x.
3) Combine 3.4 and 19.4.
5) Substract 22.8 from both sides.
6) Divide both sides by −9.6
The steps are shown below:
</span><span>3.4+2(9.7-4.8x)=61.2</span>
3.4+19.4-9.6x=61.2
22.8-9.6x=61.2
228-22.8-9.6x=61.2-22.8
-9.6x=38.4
-9.6x/-9.6=38.4/-9.6
x=-4
Answer:
true
Step-by-step explanation:
Answer:
x=8.06
Step-by-step explanation:
find you half base and use PYTHAGORAS THEOREM to find the opposite side (x)
-6+3=-3 :-) hope that help
