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IrinaVladis [17]
3 years ago
9

Identify the slope of the line shown in the graph below: slope = -1

Mathematics
2 answers:
Sav [38]3 years ago
5 0

Answer:

undefined

Step-by-step explanation:

this slope is undefined because it goes straight down and is vertical. the x and y-coordinates never change and there is no run when doing rise over run.]

pls mark brainliest

k0ka [10]3 years ago
4 0

Answer:

Vertical lines have an undefined slope. Horizontal lines have a 0 slope.

So, undefined.

Step-by-step explanation:


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What is the image of (0, 1) after a reflection over the line y = x?
hjlf

Answer:

(1,0) would be the correct answer.

Step-by-step explanation:

any point that is reflected across y=x will change unless it is on the line. if reflected across y=x, the coordinates will become y,x

8 0
3 years ago
Cause I lowkey suck at math How do I do this
dimaraw [331]
1. The slope is -2/5 not 3-/10
5 0
3 years ago
Will mark brainliest if right!!!!!!
77julia77 [94]

Answer:

sorry if wrong put b as the answer

4 0
3 years ago
Which inequality is represented by the graph? y≥35x−1.5 y≤35x−1.5 y<35x−1.5 y>35x−1.5
Setler79 [48]

Answer:

y > 0.6x - 1.5

Step-by-step Explanation:

We need two points, to get to the equation of the graph.

Since we've got the following equation for two points (x1, y1), (x2, y2):-

\boxed{ \mathsf{ \red{y - y_{1} =  \frac{y_{2} - y_{1}}{x_{2} - x_{1}} (x - x_{1})  }}}

okay soo

I found two points that lie on this graph, not on the shaded region but yeah the dotted line which defines the graph.

one point is <u>(0, -1.5)</u> which lies on the y axis(the point where the dotted line touches the y axis)

other point is <u>(2.5, 0)</u> and this lies on the x axis

placing these points in the place of (x1, y1) and (x2, y2) in the above mentioned equation

\mathsf{\implies y - ( - 1.5) =  \frac{0 -( - 1.5)}{2.5 -0 } (x -0 )}

you can take any one as (x1, y1) or (x2, y2).

so upon solving the above equation we get

\mathsf{\implies (y  +  1.5) =  \frac{0  +  1.5}{2.5  } (x  )}

\mathsf{\implies y  +  1.5 =  \frac{ 1.5}{2.5  } x  }

\mathsf{\implies y  +  1.5 =  \frac{ \cancel{1.5}\:\:{}^3}{\cancel{2.5}\:\:{}^5 } x  }

\mathsf{\implies y  +  1.5 =  \frac{ 3}{5 } x  }

multiplying both sides by 5

\mathsf{5y + 7.5 = 3x}

okay so this is the required equation of the dotted line

now we'll find the inequality

for this check whether the origin (0,0) lies under the shaded region or not

in this case it does

so

replacing x and y with 0

\mathsf{\implies5(0) + 7.5 = 3(0)}

\mathsf{\implies0 + 7.5 = 0}

this is absurd, 7.5 is not equal to 0 so we're gonna replace that equals sign with that of inequality

7.5 is greater than 0! so,

\mathsf{\implies7.5 > 0}

this goes for the whole equation, since we didnt swap any thing from left to right side of the equation or vice versa we can use this sign, to obtain the required inequality

\mathsf{5y + 7.5 > 3x}

dividing this inequality by 5, since there's no co-efficient in front of y in the given answers

we get

y + 1.5 > 0.6x

taking 1.5 to the RHS

<h3>y > 0.6x - 1.5 </h3>

that is the last option

5 0
3 years ago
Which interval describes where the graph of the function is positive?
Ad libitum [116K]

Answer:

D is the correct answer.

Step-by-step explanation:

Find the portion of the graph that is above the x-axis.

8 0
2 years ago
Read 2 more answers
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