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vodka [1.7K]
3 years ago
9

Change the repeating decimal to a fraction: 0.376376376...

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
6 0

Let <em>x</em> = 0.376376376...

Then 1000<em>x</em> = 376.376376376...

So we have

1000<em>x</em> - <em>x</em> = 376.376376376... - 0.376376376...

999<em>x</em> = 376

<em>x</em> = 376/999

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Three subtracted from the product of two and a number n
inessss [21]

Answer:

(2+n)-3

That's how you write if that is what you want.

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your class sponsors a benefit concert and the tickets at $8 each.Jordan sells 12 tickets,Andy 16,Morgan 17,and Pat 13.Compute th
Irina18 [472]
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3 years ago
Write the equation of the line y=(5)/(6)x+(7)/(6) perpendicular to
Travka [436]

Answer:

6x + 5y + 13 = 0.

Step-by-step explanation:

y = 5/6x + 7/6

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Since the line is perpendicular to y = 5/6x + 7/6

then its gradient is -6/5.

Hence its equation is: point (-8,7).

y - 7 = -6/5(x -(-8))

multiplying through by 5 we get;

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4 0
3 years ago
Estimate the maximum error made in approximating e^x by the polynomial 1 + x + {1}/{2}x^2 over the interval x of [-0.4,0.4].
kolezko [41]
E^x = 1 + x + x² / 2 + x³/ 3! + x^4 / 4! + .....
       = (1 + x + x²/2 ) + x³   [ 1/6 + x /4! + x² / 5! + ....  ]
 Error =  e^x - (1+ x + x² )   =  x³ [  1/6 + x /4! + x² / 5! + ....  ]
          x / 4!  < x / 6            x² / 5!   <  x² / 6  and so on
         So if we replace all factorials by 1/6 ..
     error  <  x² [ 1/6 + x/6 + x²/6 + ... ]
             <  x² / 6    [ 1 + x + x² ..... ]
             < x² / 6    * 1 / (1 -x)    = x² / 6 (1-x)        if   x < 1
 maximum error  =  x² /6(1-x)  occurs at 0.4 or -0.4 in the given interval.
             =  0.0444444


7 0
4 years ago
How do I solve this problem?
zubka84 [21]
All that you're basically doing is plugging in the equations to how they ask you to solve
4 0
4 years ago
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