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nordsb [41]
3 years ago
11

HELLLLPPPP PLZZZZZ I WILL MARK BRAINLEIST

Mathematics
2 answers:
Maslowich3 years ago
5 0

Answer:

5 -3

Step-by-step explanation:

NISA [10]3 years ago
4 0

Answer:

Step-by-step explanation:

4.

distance=2436-(-1020)=2436+1020=3456 ft

5.

in two turns points=3-4=-1

in 6 turns=-1/2×6=-3 points

6.

-23+40=17

she had 17 dollars balance.

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Plz help hurry i don’t understand
attashe74 [19]
Answer- Option 2

I hope that helps
7 0
3 years ago
Add: (g2 – 4g4 + 5g + 9) + (–3g3 + 3g2 – 6)
TiliK225 [7]
Group like terms

-4g^4 - 3g^3 + g^2 + 3g^2 + 5g + 9 - 6

combining like terms:-

= -4g^4 - 3g^3 + 4g^2 + 5g + 3
7 0
3 years ago
Read 3 more answers
Simplify the expression <br> 3^0
Art [367]

Answer:

1

Step-by-step explanation:

3^0

Any number (  besides 0) raised to the zero power is 1

5 0
3 years ago
Read 2 more answers
What number comes next in this pattern? 46, 49, 52, 55, 58,...
Ksenya-84 [330]

Answer:

61

Step-by-step explanation:

just add 3 to the next one

8 0
3 years ago
Read 2 more answers
Suppose that a function​ f(x) is defined for all real values of x except at xequals=c. can anything be said about the existence
Margaret [11]

we are given that

f(x) is defined for all values of x except at x=c

Limit may or may not exist

case-1:

If there is hole at x=c , then limit exist

case-2:

If there is vertical asymptote at x=c , then limit does not exist

Examples:

case-1:

\lim_{x \to c} \frac{x^2-cx}{(x-c)}

We can simplify it

\lim_{x \to c} \frac{x(x-c)}{(x-c)}

=\lim_{x \to c} x

=c

so, we can see that limit exist and it's value defined

case-2:

\lim_{x \to c} \frac{1}{(x-c)}

Left limit is

\lim_{x \to c-} \frac{1}{(x-c)}

=-\infty

Right Limit is

\lim_{x \to c+} \frac{1}{(x-c)}

=+\infty

so, we can see that left limit is not equal to right limit

so, limit does not exist

4 0
3 years ago
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