532.60
x 8.53
--------------------------------
159780
+ 2663000
42608000
---------------------------
4543.0780
We know that
1) Sandra can run a mile in 6 minutes-------> 6*60-----> 360 sec
2) 4 laps around the track equals 1 mile
so
4 laps around the track in 360 sec
1 lap in 360/4--------> 90 sec
3) the position of Sandra for t=90 sec must be equal to the point S (0,56)
I proceed to analyze each case for t=90 sec
case a) x(t)=-140 cos(pi*t/45) y(t)=112 sin(pi*t/45)
x(t)=-140 cos(pi*90/45)------> -140
y(t)=112 sin(pi*90/45)-------> 0
the position is the point (-140,0)------> is not the point S
case b) x(t)=140 sin(pi*t/90) y(t)=-112 cos(pi*t/90)
x(t)=140 sin(pi*90/90)------> 0
y(t)=-112 cos(pi*90/90)-------> 112
the position is the point (0,112)------> is not the point S
<span>
case c) x(t)=-70 sin(pi*t/45) y(t)=56 cos(pi*t/45)
</span>x(t)=-70 sin(pi*90/45)------> 0
y(t)=56 cos(pi*90/45)
-------> 56
the position is the point (0,56)------> is equal to the point S----> is the solution
case d) x(t)=70 cos(pi*t/90) y(t)=-56 sin(pi*t/90)
x(t)=70 cos(pi*90/90)------> -70
y(t)=-56 sin(pi*90/90)-------> 0
the position is the point (-70,0)------> is not the point S
therefore
the answer is the option C
x(t)=-70 sin(pi*t/45) y(t)=56 cos(pi*t/45)
Answer:
The ages of people entering a pie eating contest are normally distributed with a mean of 35 years and a standard deviation of 8.2 years.
What is the age of a pie eating contestant with a z-score of −2.1 ?
[ Age - 35 ] / [ 8.2] = -2.1 multiply both sides by 8.2
Age - 35 = -17.22 add 35 to both sides
Age ≈ 17.8 years
I am doing the test right now !!! ;P
An equation is marked out by the presence of the equality sign. From the calculation, the solution to the equation is x = 12/37.
<h3>What is equation?</h3>
The term equations refers to any mathematical statement that involves the equality sign.
Here we have the equation; 37x = 12, the first step is to divide both sides by 37 as shown;
37x/37 = 12/37
This leaves us with the result x = 12/37 which is the solution to the equation.
Learn more about equation;brainly.com/question/2263981
I think the answer is 14.
the smallest common multiple of 6 and 9 is 18. all multiples of 18 is divisible by 6 and 9.
500 ÷18=27.777777777
there are 27 numbers between 1 and 500 that are divisible by both 6 and 9, but when the quotient is an even number, the multiple of 18 is divisible by 4 as well, so only the multiples of 18 that produce an odd quotient satisfy the requirement.
from 1 to 27, there are 14 odd numbers.
