Question

A vehicle is moving at a constant speed travels 45 miles in 3/4 hour. The driver thinks he will be late to a meeting that is still 65 miles away and that starts in 1.25 hours. Assume he maintains a constant speed. Find the drivers unit rate of speed and explain whether he was late or not

Answer 1

The unit rate is 60 miles per hour and the driver will reach before time with the calculated constant speed

Step-by-step explanation:

Given

Distance = d = 45 miles

Time = t = 3/4 hour

The unit rate is defined as the distance per unit time. In this case, the unit rate can also be called speed.

So,

$s = \frac{d}{t}\\s = \frac{45}{\frac{3}{4}}\\s = 45 * \frac{4}{3}\\s = 60\ miles\ per\ hour$

Using this unit rate we can see if the car can travel 65 miles in 1.25 hours or not

Given

Distance = d1 = 65 miles

Speed = s = 60 miles per hour

Putting the values in the formula for speed

$s = \frac{d_1}{t_1}\\60 = \frac{65}{t_1}\\t_1 = \frac{65}{60}\\t_1 = 1.08\ hours$

As we can see that 1.08 is less than 1.25 so the driver will reach the meeting before time if he drives on a constant speed of 60 miles per hour

Hence,

The unit rate is 60 miles per hour and the driver will reach before time with the calculated constant speed

Keywords: Speed, unit rate

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