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xxTIMURxx [149]
3 years ago
12

Question 14 Multiple Choice Worth 1 points)

Mathematics
1 answer:
crimeas [40]3 years ago
3 0

Answer:

(22, 65)

Step-by-step explanation:

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rusak2 [61]

3:8 - 3:8

8:6 - 4:3

4:8 - 1:2

I would say that the answer is 1:2

4 0
3 years ago
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Identify the factors of 4x2 + 12x + 9.
timama [110]
(2x+3)(2x+3) is the answer. Multiply contents of brackets on each other so, 4x+6x+6x+9=4x^2+12x+9
8 0
3 years ago
50 points :)<br> 100-70=?
Marina86 [1]

Answer:

30

Step-by-step explanation:

Did you just do this for fun?

Either way have a good rest of your day!

3 0
3 years ago
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Find the x-coordinates where f ' (x)=0 for f(x)=2x+sin(4x) in the interval [0, pi]
MAVERICK [17]

Answer:

The x-coordinate is \dfrac{\pi}{6}[/tex].

Step-by-step explanation:

We are given a function f(x) as:

f(x)=2x+\sin (4x)

Now on differentiating both side with respect to x we get that:

f'(x)=2+4 \cos (4x)

When f'(x)=0

this means that 2+4\cos (4x)=0\\\\4\cos (4x)=-2\\\\\cos(4x)=\dfrac{-1}{2}

Hence, cosine function takes the negative value in second and third quadrant but we have to only find the value in the interval [0,\pi].

also we know that \cos (\dfrac{2\pi}{3})=\dfrac{-1}{2}----(1) (which lie in the second quadrant)

so on comparing our equation with equation (1) we obtain:

4x=\dfrac{2\pi}{3}\\\\x=\dfrac{\pi}{6}

Hence, the x-coordinates where f'(x)=0 for f(x)=2x+\sin(4x) is \dfrac{\pi}{6}.

5 0
3 years ago
I really dont get this please help just A, B, and C
alexandr402 [8]
The pic is kinda blurry so I can’t read it
4 0
3 years ago
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