The simplified expression for perimeter is 6w, and for area is 2w². 3 meters of a width will allow the most area while not exceeding a perimeter of 20 meters.
Step-by-step explanation:
Let w represent the width of the poster then,
The length of the poster is twice as long as its width, to mean the length is 2w
Perimeter is the distance around the figure. Your figure is a rectangle with sides width, w and length 2w;
Perimeter formula is = 2(l+w) where l is length and w is with
P=2(2w+w) = 2(3w) = 6w meters
Area is given by the product of length and width of the figure
Area=l*w
A=2w*w= 2w²
The table will be;
<u>Width in (m) Perimeter=6w in (m) Area (2w²) in m²</u>
3 6*3= 18 2*3²=2*9=18
4 6*4=24 2*4²=2*16=32
Width 3 allows for the most area while not exceeding a perimeter of 20 meters.
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Area of a rectangle figure : brainly.com/question/9624810
Keywords : rectangular poster, perimeter, area, expression
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Answer:
-5 - h
Step-by-step explanation:
ƒ(x) = 1 + 5x - x²
[f(5 + h) -f(5)]/h
= [1 + 5(5 + h) - (5 + h)² - 1 - 5(5) +5²]/h
= (25 + 5h - 25 - 10h - h² - 25 + 25)/h
= (-5h - h²)/h
= -5 - h
The difference quotient is -5 - h.
Answer:
4x12= 48. So what option gives you 48?
Step-by-step explanation:
Give the options
__6__
14 /1770. that's it if that's what ya needed.
Answer:
5(9+6)
5×9=45
5×6=30
I hope this is good enough:
