Let D = difference between mean and median of data.
Mean = (22 + 8 + 10 + 18 + 12 + 20)/6
Mean = 90/6
Mean = 15
Let m = median
m = 8, 10, 12, 18, 20, 22
m = (12 + 18)/2
m = 30/2
m = 15
D = M - m
D = 15n- 15
D = 0
D=1/2.g.t^2,
where D=distance the object has fallen, g=9.81m/sec^2(being the pull of gravity), t=time elapsed in seconds.
The initial investment = $250
<span>annual simple interest rate of 3% = 0.03
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Let the number of years = n
the annual increase = 0.03 * 250
At the beginning of year 1 ⇒ n = 1 ⇒⇒⇒ A(1) = 250 + 0 * 250 * 0.03 = 250
At the beginning of year 2 ⇒ n = 2 ⇒⇒⇒ A(2) = 250 + 1 * 250 * 0.03
At the beginning of year 3 ⇒ n = 3 ⇒⇒⇒ A(2) = 250 + 2 * 250 * 0.03
and so on .......
∴ <span>The formula that can be used to find the account’s balance at the beginning of year n is:
</span>
A(n) = 250 + (n-1)(0.03 • 250)
<span>At the beginning of year 14 ⇒ n = 14 ⇒ substitute with n at A(n)</span>
∴ A(14) = 250 + (14-1)(0.03*250) = 347.5
So, the correct option is <span>D.A(n) = 250 + (n – 1)(0.03 • 250); $347.50
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