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3 years ago

11

you own a house cleaning business. it takes you 2 hours and 45 minutes to clean a house. you have 3 houses to clean tomorrow. ho

w long would it take you to clean all three houses

1 answer:

lidiya [134]3 years ago

6 0

495 minutes. Well you will have to work put how many hours that makesim sorry

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How many vertices are in a polyhedron with 6 triangular faces?

Bingel [31]

I believe it will be 36 Im sorry if im wrong.

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Help with number 3!!

marusya05 [52]

The correct answer is B.30 inches

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Question 1,2, and 3 how do i factor those? Can you show the work and explain how?

DiKsa [7]

1: $3n^{2}+9n+6$

notice that each part is divisible by 3

$3n^{2}$ ÷ 3 = $n^{2}$

9n ÷ 3 = 3n

6 ÷ 3 = 2

so it becomes $3(n^{2} +3n+2)$

3n can be rewritten as 2n+n

-you want to rewrite it into two numbers that multiply to the number that's alone (in this case 2)

which would get you

$3(n^{2} +2n+n+2)$

Now that it's rewritten, you can factor out n + 2 from the equation.

<u><em>the answer is </em></u>

3(n+2)(n+1)

And you can check that by multiplying (n+2)(n+1) which is $n^{2} +2n+n+2$ and then each of those by 3, which is $3n^{2} +6n+3n+6$ or $3n^{2}+9n+6$ , our origional equation

2: $28+x^{2} -11x$

So I rewrote this as $x^{2} -11x+28$ (it's the same thing, just reordered using the commutative property)

now -11x can be rewritten as -4x-7x

(remember, the two numbers should multiply to equal 28, which is our constant.)

$x^{2} -4x-7x+28$

now we can factor out x from the first expression and -7 from the second

$x(x-4)-7(x-4)$

and lastly you factor out x-4,

<u><em>which would give you</em></u>

(x-4)(x-7)

Make sure to check your work and make sure it multiplies to $x^{2} -11x+28$

3: $9x^{2} -12x+4$

The first thing I notice when looking at this problem is that both 9 and 4 are perfect squares. Not only that, but they are the squares of 2 and 3, which are products of -12

So if you rewrite 9 as $3^{2}$ and 4 as $2^{2}$ , the equation becomes

$3^{2} x^{2} -12x+2^{2}$

now that $3^{2} x^{2}$ is ugly so it can be turned into $(3x)^{2}$

and -12x can be rewritten as $-2*3x*2$

so our equation now looks like $(3x)^2-2*3x*2+2^{2}$

There's a rule that says $a^{2} -2ab+b^{2} = (a-b)^{2}$

In our case, a=3x and b=2

<u><em>so the final answer is</em></u>

$(3x-2)^2$

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2 years ago

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Sphinxa [80]

5(3) + 2 =

15 + 2 =

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UNO [17]

Answer:

1/2x

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$\frac{\frac{1}{4}+x *\frac{2}{1} }{\frac{1}{2}\frac{2}{1} } =\frac{2}{4} + 2x= \frac{1}{2} + 2x$

To solve this type of fraction you need to times the inverse of the bottom fractal, both over and under. In this case the inverse of 1/2 is 2/1

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