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CaHeK987 [17]
2 years ago
8

I need the answer so my teacher doesn’t kill me

Mathematics
1 answer:
Degger [83]2 years ago
4 0
Not sure if this is what you need

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Integers
Llana [10]

Answer:

Option D is not true

Step-by-step explanation:

Whole Numbers (W) = They include Natural numbers (N) and 0.

7 0
2 years ago
I need help. once again. bahahaha
katrin [286]

Answer:

letters d. and e.

5 0
3 years ago
What is wrong with the following proof that for every integer n, there is an integer k such that n < k < n + 2? Suppose n
expeople1 [14]

Answer:

c)The proof writer mentally assumed the conclusion. He wrote "suppose n is an arbitrary integer", but was really thinking "suppose n is an arbitrary integer, and suppose that for this n, there exists an integer k that satisfies n < k < n+2." Under those assumptions, it follows indeed that k must be n + 1, which justifies the word "therefore": but of course assuming the conclusion destroyed the validity of the proof.

Step-by-step explanation:

when we claim something as a hypothesis we can only conclude with therefore at the end of the proof. so assuming the conclusion nulify the proof from the beginning

4 0
3 years ago
Thanks for your answer​
inna [77]

I hope this helps you feel free to contact me

4 0
2 years ago
Read 2 more answers
Add the first 12 terms of this sequence:<br> 15, 45, 135, 405, 1215, ...
UkoKoshka [18]

Answer:

Step-by-step explanation:

a₁ = 15

a₂/a₁ = 45/15 = 3

a₃/a₂ = 135/45 = 3

...

It is a geometric sequence with a common ratio r=3.

Sum of first 12 terms = a₁·(1-r¹²)/(1-r)

= 15·(1-3¹²)/(1-3)

= 15·(-531,441)/(-2)

= 3,985,800

7 0
2 years ago
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