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3 years ago

6

What is 13/5 as a mixed number

2 answers:

vodka [1.7K]3 years ago

5 0

2 is the base number beside 3/5

nadya68 [22]3 years ago

3 0

Answer: 2 and 3/5

Step-by-step explanation: To write an improper fraction as a mixed number, we divide the denominator into the numerator.

$\sqrt[5]{13}$ = 2 with a remainder of 3

Therefore, 13/5 can be written as the mixed number 2 and 3/5.

You might be interested in

Which of these graphs represents the inequality x > 5?

nadezda [96]

Answer:

A is correct.

x>5 means all numbers greater than BUT not equal to 5.

The open circle means "not equal".

So, A is correct.

Hope this helps!

7 0

3 years ago

Read 2 more answers

Help with math plssssss!

Olenka [21]

$\dfrac{x\sqrt3}{\sqrt{4x}}=\dfrac{x\sqrt3}{\sqrt4\cdot\sqrt{x}}=\dfrac{x\sqrt3}{2\sqrt{x}}=\dfrac{x\sqrt3\cdot\sqrt{x}}{2\sqrt{x}\cdot\sqrt{x}}=\dfrac{x\sqrt{3x}}{2x}=\dfrac{\sqrt{3x}}{2}\to\boxed{4.}\\\\Used:\\\\\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{a}\cdot\sqrt{a}=a$

6 0

3 years ago

Sliva [168]

Answer:

89 meters per second.

Step-by-step explanation:

That is quite fast!

First, we are given that in 9 sec our falcon has flown 801 meters, let's write an equation for that:

9s = 801

So in order to get s, we divide each side by 9.

Solve!

s = 801/9

s = 89

Happy learning! Please give a brainliest if you found this helpful

6 0

3 years ago

Find the Area of the figure below, composed of an isoceles trapezoid and one

MAVERICK [17]

Answer:

the total area is 15.6 square units

Step-by-step explanation:

hello,

you can find the total area dividing the shape into two known shapes

total area= area of the trapezoid +area of the semicircle

then

step one

find the area of the isosceles trapezoid using

$A=\frac{a+b}{2}*h$

where

a is the smaller base

b is the bigger base

h is theheight

A is the area

let

a=2

b=5

h=4

put the values into the equation

$A=\frac{a+b}{2}*h\\A=\frac{5+2}{2}*4\\A=3.5*4\\A=14$

Step two

find the area of the semicircle

the area of a circle is given by

$A_{c}=\pi \frac{d^{2}}{4}\\$

but, we need the area of half circle, we need divide this by 2

$A_{semic}=\frac{ \pi \frac{d^{2}}{4}}{2}\\A_{semic}= \pi \frac{d^{2}}{8}$

now the diameter of the semicircle is 2, put this value into the equation

$A_{semic}= \pi \frac{2^{2}}{8}\\\\A_{semic}= \pi \frac{1}{2}\\ A_{semic}=\frac{\pi }{2}\\$

find the total area

total area= area of the trapezoid +area of the semicircle

$total\ area= 14+\frac{\pi }{2} \\total\ area=15.6$

so, the total area is 15.6 square units

Have a good day.

5 0

4 years ago

Given that the quadratic equation has equal roots (k^2-1)x^2-2kx-3k-1=0

Alik [6]

Answer:

(See explanation for further details)

Step-by-step explanation:

The real expression is:

$(k^{2}-1)\cdot x{{2} - 2\cdot k \cdot x - 3\cdot k + 1 = 0$

The general equation for the second-order polynomial is:

$x = \frac{2\cdot k \pm \sqrt{4\cdot k^{2}-4\cdot (k^{2}-1)\cdot (-3\cdot k + 1)}}{k^{2}-1}$

This condition must be observed for the case of a quadratic equation with equal roots:

$4\cdot k^{2} - 4\cdot (k^{2}-1)\cdot (-3\cdot k + 1) = 0$

$k^{2} + (k^{2}-1)\cdot (3\cdot k + 1) = 0$

$k^{2} + 3\cdot k^{3} - 3\cdot k - k^{2}-1 = 0$

$3\cdot k^{3} - 3\cdot k - 1 = 0$

7 0

4 years ago