Answer:
no, 2^5 x 5
Step-by-step explanation:
4 is not prime and can be written as 2²
2³ x 2² x 5 = 2^5 x 5
the picture is hard
I think the equation should be
483 x 4 = h
1932 = h
20
Given: F = 11, C = 11, E=?
By Euler's formula, we have:
Hence, the solid will have 20 edges.
Take the prime factorization of .
If is a perfect cube, then the smallest that makes this happen is . We "complete" the cube by introducing just enough factors to get each prime power to be a multiple of 3.
use formula
F = 1/2*sqrt[ 4* r^2 -CD^2 ]
F = 4.4721