All categories

3 years ago

Classify the triangle shown below. Check all that apply.

Mathematics

2 answers:

Romashka [77]3 years ago

8 0

Answer:

C. and F.

Step-by-step explanation:

A scalene triangle is a triangle in which all three sides have different lengths. Also the angles of a scalene triangle have different measures. Some right triangles can be a scalene triangle when the other two angles or the legs are not congruent. Right angle are 90 degrees

Delicious77 [7]3 years ago

4 0

Answer:

C and F

Step-by-step explanation:

This triangle is not an equilateral triangle because their lengths are not equivalent to each other. It is not an isosceles triangle because no two lengths are equivalent to each other. It is a right triangle because it has one right angle(A 90 degrees angle.) It is not an obtuse triangle because there isn't an angle that is obtuse(More than 90 degrees but less than 180 degrees angle.) It isn't an acute triangle either because not all three angles are acute(Less than90 degrees angle.) Lastly, it is also a scalene triangle because none of the triangle lengths are equivalent to each other.

You might be interested in

Help me find the answer please.

sweet-ann [11.9K]

Answer:

A = 33 1/3 ft²

It's the one you picked lol

4 0

3 years ago

Read 2 more answers

How do you solve 9 yd = ? in

svp [43]

1 yd is equal to 3 ft. 1 ft is equal to 12 inches. So basically, in every one yard there is 36 inches. 36 inches times 9 yards equals the answer.

4 0

4 years ago

Suppose you cut a square into two identical triangles what type of triangles will you make

Basile [38]

Answer:

Right angled isosceles triangle.

Step-by-step explanation:

To cut a square into identical triangle one need to draw a diagonal for the square.

Suppose ABCD is the square then AC is one diagonal.

The two triangles will be

ABC and ADC

ABC has sides AB , BC and AC

ADC has sides AD, DC, AC

Since ABCD is a square its sides AB, BC , CD , DA are equal hence

for triangle ABC and ADC

side AB , BC and AD, DC will be equal

also AC is common side hence third side of both triangle is also equal .

Hence ABC and ADC are identical triangle.

___________________________________________

for triangle ABC

two sides are same in length and third is different

for triangle ABC, AB = BC but AC is not equal to AB and AC

and angle ABC is right angled as it angle of square

As two sides are equal and one angle is right angled

hence triangle ABC is right angled isosceles triangle

_______________________________________

for triangle ADC

two sides are same in length and third is different

for triangle ADC, AD= DC but AC is not equal to AD and DC

and angle ADC is right angled as it angle of square

As two sides are equal and one angle is right angled

therefore triangle ADC is right angled isosceles triangle

_________________________________________________

To understand the solution we need to draw square ABCD and diagonal AC to have better visual understanding of solution.

4 0

4 years ago

Five individuals from an animal population thought to be near extinction in a certain region have been caught, tagged, and relea

Talja [164]

Answer:

a) For this case the random variable X follows a hypergometric distribution.

b) $E(X)= n\frac{M}{N}=10 \frac{5}{25}=2$

$Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}=10\frac{5}{25}\frac{25-5}{25}\frac{25-10}{25-1}=1$

c) $P(X=0)= \frac{(5C0)(25-5 C 10-0)}{25C10}=\frac{1*184756}{3268760}=0.0565$

d) $P(X=5)= \frac{(5C5)(25-5 C 10-5)}{25C10}=\frac{1*15504}{3268760}=0.00474$

Step-by-step explanation:

The hypergometric distribution is a discrete probability distribution that its useful when we have more than two distinguishable groups in a sample and the probability mass function is given by:

$P(X=k)= \frac{(MCk)(N-M C n-k)}{NCn}$

Where N is the population size, M is the number of success states in the population, n is the number of draws, k is the number of observed successes

The expected value and variance for this distribution are given by:

$E(X)= n\frac{M}{N}$

$Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}$

a. What is the distribution of X?

For this case the random variable X follows a hypergometric distribution.

b. Compute the values for E(X) and Var(X)

For this case n=10, M=5, N=25, so then we can replace into the formulas like this:

$E(X)= n\frac{M}{N}=10 \frac{5}{25}=2$

$Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}=10\frac{5}{25}\frac{25-5}{25}\frac{25-10}{25-1}=1$

c. What is the probability that none of the animals in the second sample are tagged?

So for this case we want this probability:

$P(X=0)= \frac{(5C0)(25-5 C 10-0)}{25C10}=\frac{1*184756}{3268760}=0.0565$

d. What is the probability that all of the animals in the second sample are tagged?

So for this case we want this probability:

$P(X=5)= \frac{(5C5)(25-5 C 10-5)}{25C10}=\frac{1*15504}{3268760}=0.00474$

4 0

3 years ago

20 POINTS!

Ainat [17]

1.5, 2
When reflecting across the y-axis, the y in (x, y) stays the same but the x's sign is changed to the opposite.

8 0

4 years ago