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madam [21]
3 years ago
9

DOES SOMEONE KNOW HOW TO DO THIS???????????????????????????????????????????

Mathematics
1 answer:
Levart [38]3 years ago
7 0

Answer:

1st one is 9x-2

2nd is -3x -2

3rd one (put 1 instead of x in the given functions then calculate values and multiple )6

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Find the solution for this inequality<br> -3x + 5 &lt; 5
n200080 [17]

Answer:

2

Step-by-step explanation:

-3x+5 = 2<5

two less than 5

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3 years ago
What is the value of x in the equation<br> 1 x – 8 = 4x + 12?
Bess [88]

Answer:

The value of x is -20/3.

Step-by-step explanation:

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Solve each system by graphing -6-3x=-2y -2y=-6-3x
omeli [17]
These are the same line when you graph. So there are infinite solutions to this system. 
7 0
3 years ago
an isosceles triangle has congruent sides of 20cm. the base is 10cm. find the height of the triangle.​
dolphi86 [110]

Answer:

\large\boxed{A_\triangle=25\sqrt{15}\ cm^2}

Step-by-step explanation:

Look at the picture.

The formula of an area of a triangle:

A_\triangle=\dfrac{bh}{2}

<em>b</em><em> - base</em>

<em>h</em><em> - height</em>

<em />

We need a length of a height.

Use the Pythagorean theorem:

leg^2+leg^2=hypotenuse^2

We have:

leg=5,\ leg=h,\ hypotenuse=20

Substitute:

5^2+h^2=20^2

25+h^2=400             <em>subtract 25 from both sides</em>

h^2=375\to h=\sqrt{375}\\\\h=\sqrt{(25)(15)}\\\\h=\sqrt{25}\cdot\sqrt{15}\\\\h=5\sqrt{15}\ cm

Calculate the area:

A_\triangle=\dfrac{(10)(5\sqrt{15})}{2}=\dfrac{50\sqrt{15}}{2}=25\sqrt{15}\ cm^2

8 0
3 years ago
A ladder is placed with its foot 5m from the bottom of a wall 12m high. The top of the ladder just
Stels [109]

Answer:

13 m

Step-by-step explanation:

The ladder forms a right triangle with the wall that has legs of 5 and 12. We need to solve for the length of the ladder, which in this case, is the hypotenuse of the right triangle. You could use the Pythagorean Theorem but there's an easier way to do this. We can use the 5 - 12 - 13 Pythagorean triple so we know that the length of the ladder is 13 m.

8 0
3 years ago
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