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3 years ago

OKAY I GOING HAVE MEATEL BREAK DOWN IF SOMEONE DOES NOT HELP ME THID DUE TODAY AT 11:59PM AND I SO STRESS.

Mathematics

2 answers:

quester [9]3 years ago

4 0

Answer:

A. ?

B. ?

C. ?

1. Different

2. Same

3. Not always

4. multiplying, same, different

5. Don't know

6. and 7. don't have any students or anything so I can't answer that

Step-by-step explanation:

I kinda went off what I knew

Hey at least I tried

Maru [420]3 years ago

3 0

Answer:

6 and 7

-(1/2) and -1/2 is correct

because those students answer equals to -0.5

Step-by-step explanation:

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5y-x=10
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The average density of the material in intergalactic space is approximately 2.5 × 10–27 kg/m3. what is the volume of a lead samp

Lesechka [4]

Answer:

e. $1.8\times 10^{-6}m^3$

Step-by-step explanation:

It is given that,

The density of intergalactic space material is $2.5 \times 10^{-27}$ kg per cubic meter.

And the volume of intergalactic space material is $8.0\times 10^{24} m^3$

So the mass of that much intergalactic space material is,

$m= \rho\times v$ , where 'm' is the mass, and 'v' is the volume.

Putting the values we get,

$m=2.5 \times 10^{-27}\times 8.0 \times 10^{24}$

$m=20\times 10^{(-27+24)}=20\times 10^{-3} kg$

It is also given that the mass of lead is the same as the mass of the intergalactic space material. Therefore, the mass of lead is $20 \times 10^{-3}=2 \times 10^{-2}kg$

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$v=\frac{m}{\rho} =\frac{2 \times 10^{-2}}{11300} = 0.00000177 m^3$

$v=1.77 \times 10^{-6}=1.8\times 10^{-6}m^3$

So the volume of lead is $v=1.8\times 10^{-6}m^3$ .

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3 years ago