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bezimeni [28]
3 years ago
12

The Center for Information and Research on Civic Learning and Engagement (CIRCLE), an independent youth research organization, r

eported that 49% of all U.S. adults age 18 to 29 voted in the 2012 presidential election. We believe that a higher proportion of community college students plan to vote in the 2016 presidential election. H0: 49% of community college students plan to vote in the next presidential election. Ha: More than 49% of community college students plan to vote in the next presidential election. We survey 650 randomly selected community college students and find that 54% of them plan to vote. The P-value is approximately 0.01. At a significance level of 0.05, what can we conclude
Mathematics
1 answer:
velikii [3]3 years ago
5 0

Answer:

The evidence suggests that more than 49% of community colleges students plan to vote in the next presidential election because the p-value is less than the significance level.

Step-by-step explanation:

Given that:

The null hypothesis is:

H_o : \mu = 49 \% of community college students plan to vote in the next presidential election.

H_a : \mu > 49\%  of community college students plan to vote in the next presidential election.

sample size = 650

sample proportion = 0.54

P-value =  0.01

Level of significance = 0.05

Decision Rule: To reject the null hypothesis if the p-value is lesser than the level of significance.

Conclusion: We reject the null hypothesis and conclude that the evidence suggests that more than 49% of community colleges students plan to vote in the next presidential election because the p-value is less than the significance level.

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Act like it's a whole circle and find the perimeter, then divide by 2.

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Find the interval of convergence of the power series. (Be sure to include a check for convergence at the endpoints of the interv
sleet_krkn [62]

Answer:

(0, 16]

Step-by-step explanation:

∑ₙ₌₁°° (-1)ⁿ⁺¹ (x−8)ⁿ / (n 8ⁿ)

According to the ratio test, if we define L such that:

L = lim(n→∞) |aₙ₊₁ / aₙ|

then the series will converge if L < 1.

aₙ = (-1)ⁿ⁺¹ (x−8)ⁿ / (n 8ⁿ)

aₙ₊₁ = (-1)ⁿ⁺² (x−8)ⁿ⁺¹ / ((n+1) 8ⁿ⁺¹)

Plugging into the ratio test:

L = lim(n→∞) | (-1)ⁿ⁺² (x−8)ⁿ⁺¹ / ((n+1) 8ⁿ⁺¹) × n 8ⁿ / ((-1)ⁿ⁺¹ (x−8)ⁿ) |

L = lim(n→∞) | -n (x−8) / (8 (n+1)) |

L = (|x−8| / 8) lim(n→∞) | n / (n+1) |

L = |x−8| / 8

For the series to converge:

L < 1

|x−8| / 8 < 1

|x−8| < 8

-8 < x−8 < 8

0 < x < 16

Now we check the endpoints.  If x = 0:

∑ₙ₌₁°° (-1)ⁿ⁺¹ (0−8)ⁿ / (n 8ⁿ)

∑ₙ₌₁°° -(-1)ⁿ (-8)ⁿ / (n 8ⁿ)

∑ₙ₌₁°° -(8)ⁿ / (n 8ⁿ)

∑ₙ₌₁°° -1 / n

This is a harmonic series, and diverges.

If x = 16:

∑ₙ₌₁°° (-1)ⁿ⁺¹ (16−8)ⁿ / (n 8ⁿ)

∑ₙ₌₁°° (-1)ⁿ⁺¹ (8)ⁿ / (n 8ⁿ)

∑ₙ₌₁°° (-1)ⁿ⁺¹ / n

This is an alternating series, and converges.

Therefore, the interval of convergence is:

0 < x ≤ 16

Or, in interval notation, (0, 16].

4 0
3 years ago
X2+4x+3 can someone explain ?
Katyanochek1 [597]

Answer:

Factor: (x+1) (x+3)

Step-by-step explanation:

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