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Vsevolod [243]
4 years ago
14

A piece of chalk is 34/56 centimeter long. Brian breaks off 23/56 centimeter long. Sara added 12/56 centimeter to the chalk that

was left. How long is the piece of chalk that is left? Write and solve an equation.
Mathematics
1 answer:
mr Goodwill [35]4 years ago
7 0

Answer:

23/56 centimeters

Step-by-step explanation:

all of the variables have a common denominator, so you can effectively ignore the denominator when solving.

1. you start off with 34/56 centimeter of chalk and Brian breaks off 23/56 centimeters worth, leaving you with 11/56 centimeters

\frac{34}{56} -\frac{23}{56} =\frac{11}{56}

2. Sara then added 12/56 centimeters worth, making the final amount 23/56 centimeters of chalk

\frac{11}{56}+\frac{12}{56} =\frac{23}{56}

An equation to summarize all of this is:

\frac{34}{56} -\frac{23}{56} +\frac{12}{56}

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5.2 I am guessing.

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3 years ago
(-18x^2+12x-2)*(x^3+12x^2+48x+64)
prohojiy [21]
<h2>Answer:</h2>

-18x^5-204x^4-722x^3-600x^2+672x-128

<h2>Explanation:</h2>

( - 18 {x}^{2}  + 12x - 2)

( {x}^{3}  + 12 {x}^{2}  + 48x + 64)

There are multiple ways to solve this for example the foil method or the box method. I prefer to do the box method.

First we are going to set it up

After we set it up we have to solve it so first we are going to multiply

{x}^{3}  \times  - 18 {x}^{2}  =  - 18 {x}^{5}

We have to add the exponent

- 18 {x}^{2}  \times 12 {x}^{2}  =  - 216 {x}^{4}

- 18 {x}^{2}  \times 48x =  - 864 {x}^{3 }  \\  - 18{x}^{2}  \times 64 =  - 1152 {x}^{2}  \\ 12x \times  {x}^{3}  = 12 {x}^{4}  \\ 12x \times 12 {x}^{2}  = 144 {x}^{3}

12x \times 48x = 576 {x}^{2}  \\ 12x \times 64 = 768x

- 2  \times  {x}^{3}  =  - 2 {x}^{3}  \\  - 2 \times 12 {x}^{2}  =  - 24 {x}^{2}  \\  - 2 \times 48x =  - 96x \\  - 2 \times 64 =  - 128

Now we have to add them

-18x^5 stays because there is nothing to add to

Now we add the rest

-216 {x}^{4}  + 12 {x}^{4}  =  - 204 {x}^{4}

- 864 {x}^{3}  + 144 {x}^{3}  +  - 2 {x}^{3}  = -  722 {x}^{3}

768x - 96x = 672x

And -128 stays the same

- 1152 {x}^{2}  + 576 {x}^{2}  - 24 {x}^{2}  =  - 600 {x}^{2}

The answer is

-18x^5-204x^4-722x^3-600x^2+672x-128

5 0
4 years ago
the temperature of dry ice is -109.5°F this is 184.2°F less than the outside temperature. What is the outside temperature?
AlladinOne [14]

Answer:

<em>74.7°F</em>

Step-by-step explanation:

You need to add 184.2°F to -109.5°F.

184.2°F + (-109.5°F) =

= 184.2°F - 109.5°F

= 74.7°F

4 0
3 years ago
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