For question 11, you essentially need to find when h(t) = 0, since that is when the height of the ball reaches 0 (ie touches the ground).
For question 12, it is asking for a maximum height, so you need to find when dh/dt = 0 and taking the second derivative to prove that there is maximum at t. That will find you the time at which the ball will hit a maximum height.
Rinse and repeat question 12 for question 13
P=4*a, where P - perimeter, a - length of one side of the square.
if a=x+3 and P=48, then 4(x+3)=48;
x=9.
Answer: 9 units.
well L x W x H = 448³ x 12 x 8 = <span>2<span>²³
so your answer is 2²³</span></span>
Answer:
This function represents a direct variation because it passes through the origin and has a constant rate
Answer:
Step-by-step explanation:
<u>Answer choices:</u>
A) Asher made errors in multiplication.
- No, the products are correct
B) Asher found multiples of 10, not factors of 10.
C) Asher should have multiplied 10 × 4 as well.
- No, 4 is not one of the factors of 10
D) Asher should have gotten this as the answer: 1, 2, 5, and 10.
- Yes, these are the true factors of 10
E) Asher should have gotten this as the answer: 10, 20, 30, 40, …
- No, the correct one is one before
