Add up 18 and 30. You'll get 48. Then 18/48 of the class is female. Of course this could be simplified: 18/48 = 3/8. Then 3/8 of the class is female and 5/8 is male.
There are a few ways to solve this, the simplest of which is probably factoring. Start by finding factors of C (10) that add up to be B (-2).
fac(10) { -10, 1 ; -5, 2 }
Well, there are no factors of 10 that can add to b - so we will use the quadratic formula.
(-b +- sqrt(b^2 - 4ac)) / 2a
where a = 1, b = -2, c = 10
b^2 - 4ac = (-2)^2 - 4(1)(10) = 4 - 40 = -36
-b +- sqrt(-36) / 2a
(2 +- sqrt(-36)) / 2
sqrt(-36)
sqrt(-1 * 36)
sqrt(-1) * sqrt(36)
i * 6
6i
2 + 6i / 2 ; 1 + 3i
2 - 6i / 2 ; 1 - 3i
Solutions: 1 + 3i, 1 - 3i
10+4 or 3 + 11 these are some of them
Answer:
Yes, it is possible if the sweaters on sale are $7.40 each.
Step-by-step explanation:
The sweaters each cost $37. To purchase all four (for herself and 3 sisters) without a sale would be 4(37)= $148.
40% off the regular price would be 0.40(148)= $59.20 savings. She would spend 148-59.2= $88.80.
Is it possible to buy two regular price sweaters and two on sale for $88.80?
2(37)=$74. If we subtract from the sales total, 88.80-74=14.80. This means the two sweaters on sale must each be $7.40. It is possible to save 40%.
Answer:
26.4%
Step-by-step explanation:
PLS GIVE BRAINLIEST
