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jenyasd209 [6]
2 years ago
7

I need help with number 1-73

Mathematics
1 answer:
lora16 [44]2 years ago
7 0
1-73
a) x^7*x^4 = x^11
b) (x^3)^3 = x^9
c) m^14/m^2 = m^12
d) (x^2y^2)^4 = x^8y^8
e) x^5y^11 / x^2y^3 = x^3y^8
f) 2x^12/8x^2 = x^10 / 4

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Kryger [21]
What????? Um I’m so sorry I don’t know
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The owner of a toy store received a shipment of 1,552 party favors. The party favors came in 28 boxes. The same number of party
Svetradugi [14.3K]

let 


x = the number of party favors in each of the 27 boxes

y = the number of party favors in the last box


the total number of party favors is 1,552


27x + y = 1,552


since 1552 = 57*27 + 13


if we assume that y<x we conclude that there are 57 party favors in each of the 27 boxes and 13 party favors in the last box.



Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

8 0
3 years ago
Y = (x-3)^2 when x = 9
Strike441 [17]

Answer:

36

Step-by-step explanation:

9-3=6

6*6=36

3 0
3 years ago
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What does the discriminant determine?
devlian [24]
The discriminant is the part of the quadratic formula underneath the square root symbol: b²-4ac. The discriminant tells us whether there are two solutions, one solution, or no solutions.
6 0
2 years ago
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The Key Club is having a fundraising dinner for charity. The venue that holds a maximum of 500 people will
Alexus [3.1K]

Answer:

\dfrac{\$1000+\$20x}{x} \leq \$25

Minimum 200 people other than the 2 charity representatives.

Step-by-step explanation:

Given that:

The venue can hold a maximum of 500 people.

Cost of venue = $1000

Per person cost for food = $20

Two charity representatives get to attend the dinner for free.

To find:

The inequality and to determine how many people must come to keep costs at most $25.

Solution:

Let the number of people attending the dinner = x

Cost of food for x people = \$20x

Total cost = $1000 + \$20x

Cost per person = Total cost divided by Number of people attending the dinner.

As per question statement:

\dfrac{\$1000+\$20x}{x} \leq \$25\\\Rightarrow 1000+20x\leq25x\\\Rightarrow 1000 \leq 5x\\\Rightarrow x\geq 200

Therefore, the answer is:

Minimum 200 people other than the 2 charity representatives should attend the dinner.

8 0
3 years ago
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