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3 years ago

One hundred fifty is what percent of 200?

1 answer:

8 0

$Method\ 1:\\\\\dfrac{150}{200}\cdot100\%=\dfrac{15}{20}\cdot100\%=15\cdot5\%=75\%\\\\Method\ 2:\\\\200\ -\ 100\%\\150\ -\ p\%\\\\cross\ multiply\\\\200\cdot p=150\cdot100\\200p=15,000\ \ \ |divide\ both\ sides\ by\ 200\\\boxed{p=75\ (\%)}$

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Write the equation in point slope form of the line that passes through the given point with the given slope (4,-11);m=3/4

Triss [41]

Answer:

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4 0

3 years ago

Question~

Rasek [7]

Answer:

B. 1

Step-by-step explanation:

Multiply the first term by $x^a$ , the second term by $x^b$ , the third term by $x^c$ .

The first term becomes:

$x^a/(x^a+x^b+x^c)$

The second term becomes:

$x^b/(x^a+x^b+x^c)$

The third term becomes:

$x^c/(x^a+x^b+x^c)$

Their sum is:

$(x^a+x^b+x^c)/(x^a+x^b+x^c) = 1$

Correct choice is B

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2 years ago

A bin contains 25 light bulbs, 5 of which are in good condition and will function for at least 30 days, 10 of which are partiall

Ira Lisetskai [31]

Answer:

The probability that it will still be working after one week is $\frac{1}{5}$

Step-by-step explanation:

Given :

Total number of bulbs = 25

Number of bulbs which are good condition and will function for at least 30 days = 5

Number of bulbs which are partially defective and will fail in their second day of use = 10

Number of bulbs which are totally defective and will not light up = 10

To find : What is the probability that it will still be working after one week?

Solution :

First condition is a randomly chosen bulb initially lights,

i.e. Either it is in good condition and partially defective.

Second condition is it will still be working after one week,

i.e. Bulbs which are good condition and will function for at least 30 days

So, favorable outcome is 5

The probability that it will still be working after one week is given by,

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}$

$\text{Probability}=\frac{5}{25}$

$\text{Probability}=\frac{1}{5}$

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3 years ago

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Pie

Answer:

Step-by-step explanation:

the answer is 69 bc it is correct

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3 years ago

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\begin{cases}
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6 0

3 years ago