Answer:
![\sqrt{93}](https://tex.z-dn.net/?f=%5Csqrt%7B93%7D)
Step-by-step explanation:
8^2+5^2=c^2
64+25=c^2
89=c^2
c=
<-- this is the length of the rectangle at the bottom
2^2+(
)^2=c^2
4+89=c^2
c=
<-- length of dotted line (diagonal)
Given:
and
.
To find:
The value of f(5).
Solution:
We have,
![f(n)=f(n-1)-4](https://tex.z-dn.net/?f=f%28n%29%3Df%28n-1%29-4)
For
,
![f(2)=f(2-1)-4](https://tex.z-dn.net/?f=f%282%29%3Df%282-1%29-4)
![f(2)=f(1)-4](https://tex.z-dn.net/?f=f%282%29%3Df%281%29-4)
![f(2)=10-4](https://tex.z-dn.net/?f=f%282%29%3D10-4)
![f(2)=6](https://tex.z-dn.net/?f=f%282%29%3D6)
For
,
![f(3)=f(3-1)-4](https://tex.z-dn.net/?f=f%283%29%3Df%283-1%29-4)
![f(3)=f(2)-4](https://tex.z-dn.net/?f=f%283%29%3Df%282%29-4)
![f(3)=6-4](https://tex.z-dn.net/?f=f%283%29%3D6-4)
![f(3)=2](https://tex.z-dn.net/?f=f%283%29%3D2)
For
,
![f(4)=f(4-1)-4](https://tex.z-dn.net/?f=f%284%29%3Df%284-1%29-4)
![f(4)=f(3)-4](https://tex.z-dn.net/?f=f%284%29%3Df%283%29-4)
![f(4)=2-4](https://tex.z-dn.net/?f=f%284%29%3D2-4)
![f(4)=-2](https://tex.z-dn.net/?f=f%284%29%3D-2)
For
,
![f(5)=f(5-1)-4](https://tex.z-dn.net/?f=f%285%29%3Df%285-1%29-4)
![f(5)=f(4)-4](https://tex.z-dn.net/?f=f%285%29%3Df%284%29-4)
![f(5)=-2-4](https://tex.z-dn.net/?f=f%285%29%3D-2-4)
![f(5)=-6](https://tex.z-dn.net/?f=f%285%29%3D-6)
Therefore, the value of
is
.
Division , timetable , adding , and subtracting