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Setler [38]
3 years ago
10

Evaluate the following logarithmic expression without the use of a calculator. Enter your answer as a fraction reduced to the lo

west terms. ln(\sqrt[7]{e4})
Mathematics
1 answer:
Leni [432]3 years ago
3 0
Assuming you meant <span>e⁴  thus
</span>

\bf ln\left( \sqrt[7]{e^4} \right)\implies log_e\left( e^{\frac{4}{7}} \right)\\\\&#10;-----------------------------\\\\&#10;log_{{  a}}{{  a}}^x\implies x=x\impliedby \textit{let's use this cancellation rule}\\\\&#10;-----------------------------\\\\&#10;log_e\left( e^{\frac{4}{7}} \right)\iff \cfrac{4}{7}
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A college financial adviser is interested in studying the number of students at his college who apply for loans when entering gr
Shalnov [3]

Answer:

0.7429

Step-by-step explanation:

Given that  Of the 721 students at the college, 299 of them apply for loans when entering graduate school.

So p = proportion of students applying for loans = \frac{299}{721} =0.415

Each student is independent of the other and there are two outcomes

Hence out of 45 students the no of students who apply for loans say X is binomial with n =45 and p = 0.415

the probability that more than 16 of them apply for loans

=P(X>16)\\= \Sigma_{x=17} ^{45}  P(x)\\=\Sigma_{x=17} ^{45}(45Cx (0.415)^x (0.585)^{25-x} )

=0.7429

4 0
3 years ago
What is the quotient? 1462 divided 58 Enter your answer as a mixed number in the simplest form
stepan [7]
The answer would be 25.2or 126/5
8 0
3 years ago
Read 2 more answers
How many solutions are there in this equation 8 (x-3)=8x-24
kari74 [83]
Performing the indicated multiplication on the left side gives you:

8x-24=8x-24,

8x=8x

1=1 

These expressions are true for any real value of x and thus has infinitely many solutions...
3 0
3 years ago
Read 2 more answers
How many times longer is the wavelength of a sound wave with a frequency of 20 waves per second than the wavelength of a sound w
sergejj [24]

The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

<h3>Calculating wavelength </h3>

From the question, we are to determine how many times longer is the first sound wave compared to the second sound water

Using the formula,

v = fλ

∴ λ = v/f

Where v is the velocity

f is the frequency

and λ is the wavelength

For the first wave

f = 20 waves/sec

Then,

λ₁ = v/20

For the second wave

f = 16,000 waves/sec

λ₂ = v/16000

Then,

The factor by which the first sound wave is longer than the second sound wave is

λ₁/ λ₂ = (v/20) ÷( v/16000)

= (v/20) × 16000/v)

= 16000/20

= 800

Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

Learn more on Calculating wavelength here: brainly.com/question/16396485

#SPJ1

6 0
2 years ago
What is the slope and y intercept of y=-x+3
sattari [20]
Y intercept when x =0

<span> y=-x+3
 y = -0 +3
 y = 3

</span><span> the slope is -1 </span>
<span>
</span>
8 0
3 years ago
Read 2 more answers
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